Question
Here is the graph of the function y=2x^2+2x-7 Jse the graph to estimate the solutions to the equation 2x^2+2x-7=0
Answer
4.6
(227 Votes)
Zebulon
Professional · Tutor for 6 years
Answer
The solutions to the equation are \(x = \frac{-2 + \sqrt{(2)^2 - 4*2*(-7)}}{2*2}\) and \(x = \frac{-2 - \sqrt{(2)^2 - 4*2*(-7)}}{2*2}\).
Explanation
## Step 1: Identify the type of the equation. The given equation is a quadratic equation. A quadratic equation is of the form
, where
,
, and
are constants, and
is the variable.## Step 2: Identify the values of
,
, and
in the given equation. In the equation
,
,
, and
.## Step 3: Use the quadratic formula to find the solutions to the equation. The quadratic formula is given by:###
## Step 4: Substitute the values of
,
, and
into the quadratic formula and solve for
.