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Divide: (2x^4+5x^3+6x-1)/(x+3) A. 2x^3+11x^2+39x+117+(350)/(x+3) B 2x^3-x^2+9x-27+(80)/(x+3) C 2x^3+11x^2+33x+105+(314)/(x+3) D.

Question

Divide: (2x^4+5x^3+6x-1)/(x+3) A. 2x^3+11x^2+39x+117+(350)/(x+3) B 2x^3-x^2+9x-27+(80)/(x+3) C 2x^3+11x^2+33x+105+(314)/(x+3) D. 2x^3-x^2+3x-3+(8)/(x+3)

Answer

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Verificación de expertos
Dylan Elite · Tutor for 8 years

Answer

The provided expression is a polynomial long division problem. We start by dividing the highest term of the numerator by the highest term of the denominator.Dividing by results into . Then multiply by to get , and subtract this from the first two terms in the numerator. This is shown as: .Next, include down the next term from the numerator and repeat the process. Divide by to get , multiply by to get and subtract it from to get .For the next step, we bring down the last term from the numerator and divide by to get , multiply onto to become . Subtract from leaving us .Finally, divide by to yield , calculate and subtract from to get the rest as . This rest is then written as a fraction over the denominator . As a result, the quotient obtained is , which is answer D.