What mass of sodium chloride is when chlorine gas reacts with 0.29 grams of sodium iodide? The unbalanced equation is given below: Nal(s)+Cl_(2)(g)arrow NaCl(s)+b(g)

## Step 1The first step in solving this problem is to balance the given chemical equation.The unbalanced equation is: After balancing, the equation becomes: ## Step 2Next, we need to convert the mass of sodium iodide (NaI) into moles. The molar mass of NaI is calculated by adding the atomic masses of sodium (Na, 22.989769 gm/mol) and iodine (I, 126.90447 gm/mol), which equals 149.89424 gm/mol.### ## Step 3The stoichiometry of the balanced chemical equation shows that one mole of NaI produces one mole of NaCl. Therefore, the number of moles of NaI is equal to the number of moles of NaCl.## Step 4The mass of NaCl produced can be calculated by multiplying the number of moles of NaCl by its molar mass. The molar mass of NaCl is calculated by adding the atomic masses of sodium (Na, 22.989768 gm/mol) and chlorine (Cl, 35.45 gm/mol), which equals 58.44 gm/mol.###