Question
Look at the equation showing the splitting of water to give hydrogen and oxygen . Use it to find the energy released by forming bonds in this reaction. You will need some of the bond energies from the table. Enter your answer as a number kJ/mol 2H_(2)Oarrow 2H_(2)+O_(2) Bond Bond energy (kJ/mol) Harrow H 436 O=O 498 H-O 464 C-H 413 C=0 803 Nequiv N 945 N+A 391 243 H-Cl 432
Answer
4.6
(305 Votes)
Matilda
Veteran · Tutor for 10 years
Answer
### 486 kJ/mol
Explanation
## Step 1: Identify Bonds Broken in Reactants### In the reaction
, each water molecule (
) has two
bonds. Therefore, for 2
molecules, a total of 4
bonds are broken.## Step 2: Calculate Energy Required to Break Bonds### The bond energy for
is 464 kJ/mol. Thus, the total energy required to break 4
bonds is
kJ.## Step 3: Identify Bonds Formed in Products### In the products, 2
molecules are formed, each with one
bond, and 1
molecule is formed with one
bond. Therefore, 2
bonds and 1
bond are formed.## Step 4: Calculate Energy Released by Forming Bonds### The bond energy for
is 436 kJ/mol, and for
is 498 kJ/mol. Thus, the total energy released by forming 2
bonds and 1
bond is \((2 \times 436) + 498 = 872 + 498 = 1370\) kJ.## Step 5: Determine Net Energy Change### The net energy change is the difference between the energy required to break the bonds and the energy released by forming the bonds:
kJ.#