Find the missing number in this pair of equivalent fractions (1)/(?)=(6)/(30)

The given problem is to find a missing number in a pair of equivalent fractions: Solving this problem means finding the denominator (let's denote this "?") that would make two fractions equivalent where:The fraction on the left has 1 as its numerator and '?' as its denominator, and the fraction on the right has 6 as its numerator and 30 as its denominator.The rule in finding equivalent fractions is that you just multiply or divide both the numerator and denominator by the same number. We can apply this rule to the given problem by considering our numerator-to-demoninator ratio.Answer:Looking at the fraction on the right side, we see that the number 30 appears 5 times larger than the number 6. If we treat the fraction on the right as our "standard form," then we should reduce it to its lowest term to make the equation simpler.Let's divide both numerator and denominator by 6: So the fraction in the right side becomes .Now let's move on to the fraction on the left side. The right fraction tells us that for every one part represented by the numerator, there are 5 parts represented in whole, the denominator. Therefore, our denominator of the left side should be 5 to make two fractions equivalent.Therefore,Our '?' is equivalent to *5*.