12. Avolmeter has a resistance of 40 A voltmeter has a resistance of 4.0kQ and reads 1.0 V for every scale division on the meter. A power supply of emf 20 V and negigble internal resistance is connected across this voltmeter. and a resistor in series. The voltmeter reads two divisions. What is the value of the resistor? A 44kOmega B 36kOmega C 4.4kOmega D 3.6kOmega

## Step 1:The problem provides us with the information that the voltmeter reads 1.0 V for every scale division. Since the voltmeter is reading two divisions, the total voltage across the voltmeter and the resistor in series is .## Step 2:We know that the total voltage supplied by the power supply is . Therefore, the voltage across the resistor can be found by subtracting the voltage across the voltmeter from the total voltage supplied. This can be calculated using the formula: ### ## Step 3:Ohm's law states that the resistance of an object is equal to the voltage across it divided by the current through it. We know that the current through the resistor and the voltmeter is the same because they are in series. Therefore, we can find the resistance of the resistor by dividing the voltage across the resistor by the current through the circuit. The current can be found by dividing the voltage across the voltmeter by its resistance. This can be calculated using the formula: ###