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17. In Right Triangle Delta ABC Shown Below, the Given Lengths Are in Millimeters .What Is SinA A. (4sqrt (2))/(9) B. (4sqrt (2))/(7)

Question

17. In right triangle Delta ABC shown below, the given lengths are in millimeters .What is sinA A. (4sqrt (2))/(9) B. (4sqrt (2))/(7) C. (7sqrt (2))/(8) D. . (7)/(9) E. . (9)/(7)

Answer

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Answer

To find in right triangle , we need to identify the lengths of the sides relative to angle A. In a right triangle, the sine of an angle is the ratio of the length of the opposite side to the length of the hypotenuse.Given:- AB = mm (opposite side to angle A)- BC = 7 mm (adjacent side to angle A)- AC = 9 mm (hypotenuse)Since is the ratio of the length of the side opposite to angle A to the length of the hypotenuse, we have: Now we substitute the given lengths: Therefore, the correct answer is:A.