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a student recorded the acceleration of a trolley down a ramp. 0.7m/s^2, 0.6m/s^2, 0.8m/s^2, 0.8m/s^2 calculate the mean acceleration to

Question

A student recorded the acceleration of a trolley down a ramp. 0.7m/s^2, 0.6m/s^2, 0.8m/s^2, 0.8m/s^2 Calculate the mean acceleration to 1 decimal place.

Answer

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Answer

Interpretation of Question:The student has collected multiple readings of the acceleration of the trolley. The various readings are 0.7 m/s^2, 0.6 m/s^2, 0.8 m/s^2, and 0.8 m/s^2. To find the mean acceleration, we need to add all these readings and divide by the total number of readings.Approach:To calculate the mean (or average) of a set of numbers, follow these steps:1. Add up all the numbers.2. Divide by the count of the numbers Solution Steps:1. First, let's add the given acceleration readings:0.7 + 0.6 + 0.8 + 0.8 = 2.9 m/s^2 2. Count the number of readings. There are total 4 readings.3. Divide the sum by the number of readings:2.9 m/s^2 / 4 = 0.725 m/s^2While answering the mean value is 0.725 m/s^2, but as the question asks for the answer till 1 decimal place, we need to round the answer. Rounding 0.725 to one decimal place gets us 0.7 m/s^2.So,The mean acceleration of the trolley down a ramp is 【Answer】: 0.7 m/s^2, to 1 decimal place.