S-wave Challengel Example 17: An S-wave arrived at a seismic station 6,2 oo km away at 04:48:00 What time did the fixe P-wave arrive at this station?

#ExplanationTo solve this problem, we need to understand the properties of P-waves and S-waves. P-waves, or primary waves, are the fastest seismic waves and the first to be recorded by a seismograph in the event of a disturbance, such as an earthquake. S-waves, or secondary waves, are slower and arrive after the P-waves.The average speed of P-waves is about 6 km/s, while the average speed of S-waves is about 3.5 km/s. We can use these average speeds to calculate the arrival times of the P-wave and S-wave at a seismic station that is a certain distance away.Given that the S-wave arrived at the seismic station 6,200 km away at 04:48:00, we can calculate the time it took for the S-wave to travel this distance. Using the average speed of S-waves (3.5 km/s), we find:Time = Distance / SpeedTime = 6,200 km / 3.5 km/s = 1,771.43 secondsConverting this time to hours, minutes, and seconds, we get approximately 0.49 hours, or 29 minutes and 31 seconds.Since the S-wave arrived at 04:48:00, the earthquake must have occurred at approximately 04:18:29 (04:48:00 - 00:29:31).Now, we can calculate the time it would take for a P-wave to travel the same distance. Using the average speed of P-waves (6 km/s), we find:Time = Distance / SpeedTime = 6,200 km / 6 km/s = 1,033.33 secondsConverting this time to hours, minutes, and seconds, we get approximately 0.29 hours, or 17 minutes and 13 seconds.So, the P-wave would have arrived at the seismic station at approximately 04:35:42 (04:18:29 + 00:17:13).#AnswerThe P-wave arrived at the seismic station at approximately 04:35:42.