Boron has an average atomic mass of 10.81. One isotope of boron has a mass of 10.012938 and relative abundance of 19.80% . The other isotope has a relative abundance of 80.20% . What is the mass of that isotope? Report to two decimal places. square amu DONE

## Step 1:Identify the given values:- Average atomic mass ( ) = 10.81 amu- Mass of the first isotope ( ) = 10.012938 amu- Relative abundance of the first isotope ( ) = 19.80% or 0.198- Relative abundance of the second isotope ( ) = 80.20% or 0.802## Step 2:Use the formula for average atomic mass:### ## Step 3:Substitute the known values into the formula and solve for the mass of the second isotope ( ):### ## Step 4:Calculate the product of the first isotope's abundance and mass:### ## Step 5:Subtract this value from the average atomic mass to isolate the second isotope term:### ## Step 6:Divide this result by the abundance of the second isotope to find its mass:### #