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A 1.8 g potato core is submerged in sugar water. When it is removed, its mass is 1.6 g. What is the percentage loss of the potato's mass? F Round your an swer to the neare st hundredth of a percent.

Question

A 1.8 g potato core is submerged in sugar
water. When it is removed, its mass is 1.6 g.
What is the percentage loss of the potato's
mass? F Round your an swer to the neare st
hundredth of a percent.

A 1.8 g potato core is submerged in sugar water. When it is removed, its mass is 1.6 g. What is the percentage loss of the potato's mass? F Round your an swer to the neare st hundredth of a percent.

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JoshuaVeteran · Tutor for 12 years

Answer

11%

Explain

The percentage loss or decrease in any quantity is also calculated using somewhat the similar formula: \[ \left( \frac{{\text{{old value}} - \text{{new value}}}}{\text{{old value}}} \right) \times 100 \] In this problem, the old value (the initial mass of the potato core) is \(1.8 \, \text{g}\) and the new value (the mass after submerging in sugar water) is \(1.6 \, \text{g}\). Plugging these amounts into the formula gives: \[ \left( \frac{{1.8 \, \text{g} - 1.6 \, \text{g}}}{1.8 \, \text{g}} \right) \times 100 = 0.11 \times 100= 11\% \] Therefore, the percentage mass loss of the potato core is \(11\%\). <br /><br />This means the mass of the potato core decreased by \(11\%\) after being submerged in sugar water.
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