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9. In cats, the gene for calico (multicolored) cats is codominant. Females that receive.a B ànd an R gene have black and oRange sploches on white coats. Males can only be black or orange, but rarely calico. Show the cross of a female calico cat with a black male; Female, calico=X^BXR Male, black=X^BY How many offspring will be: Female and calico __ Female and black __ Male and black __ Male and orange __ Male and calico __

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9. In cats, the gene for calico (multicolored) cats is codominant. Females that receive.a B ànd an R gene
have black and oRange sploches on white coats. Males can only be black or orange, but rarely calico.
Show the cross of a female calico cat with a black male;
Female, calico=X^BXR Male, black=X^BY
How many offspring will be:
Female and calico __ Female and black __
Male and black __	Male and orange __
Male and calico __

9. In cats, the gene for calico (multicolored) cats is codominant. Females that receive.a B ànd an R gene have black and oRange sploches on white coats. Males can only be black or orange, but rarely calico. Show the cross of a female calico cat with a black male; Female, calico=X^BXR Male, black=X^BY How many offspring will be: Female and calico __ Female and black __ Male and black __ Male and orange __ Male and calico __

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JeromeProfessional · Tutor for 6 years

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To solve this genetics problem, we will perform a Punnett square cross between a female calico cat and a black male cat. The female calico cat has the genotype \(X^{B}X^{R}\), indicating that she has one X chromosome with the black color gene (B) and another X chromosome with the orange color gene (R). The male black cat has the genotype \(X^{B}Y\), indicating that he has one X chromosome with the black color gene and a Y chromosome, which does not carry a color gene.Here's how the Punnett square would look:``` X^B (Male) Y (Male)--------------------------------X^B (Female) | X^BX^B | X^BY--------------------------------X^R (Female) | X^BX^R | X^RY```Now let's fill in the Punnett square with the possible genotypes of the offspring:``` X^B (Male) Y (Male)--------------------------------X^B (Female) | X^BX^B | X^BY--------------------------------X^R (Female) | X^BX^R | X^RY```From the Punnett square, we can determine the genotypes of the offspring:- \(X^{B}X^{B}\): Female and black- \(X^{B}Y\): Male and black- \(X^{B}X^{R}\): Female and calico- \(X^{R}Y\): Male and orangeNow, let's count the number of each type of offspring:- Female and calico: 1 (X^BX^R)- Female and black: 1 (X^BX^B)- Male and black: 1 (X^BY)- Male and orange: 1 (X^RY)- Male and calico: 0 (Males cannot be calico because they have only one X chromosome, and calico requires both the B and R genes on two different X chromosomes)Final answer:- Female and calico: 1- Female and black: 1- Male and black: 1- Male and orange: 1- Male and calico: 0
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