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(2x+3)(3x+4) +17x+7 6x^2+9x+12 6x^2+8x+12 6x^2+17x+12

Question

(2x+3)(3x+4)
+17x+7
6x^2+9x+12
6x^2+8x+12
6x^2+17x+12

(2x+3)(3x+4) +17x+7 6x^2+9x+12 6x^2+8x+12 6x^2+17x+12

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MeredithMaster · Tutor for 5 years

Answer

The problem seems to have some erroneous entries. Let's consider the given problem in sequence:<br /><br />1. Expand $(2x+3)(3x+4)$: The result of this step is $6x^{2}+17x+12$.<br /><br />Any further steps in context are uncalled for as the provided prompt doesn't mention any further calculations.<br /><br />So, the solution to the multiplication $(2x+3)(3x+4)$ is $6x^{2}+17x+12$.
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