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(ii) Describe what happerm at the negative electrode. __ (iii) Complete the half equation for the reaction at the positive electrode. arrow Cl_(2)+ Magnesium can be produced from magnesium oxide. The equation for the reaction is: Si(s)+2MgO(s)arrow SiO_(2)(s)+2Mg(g) (i) How can you tell from the equation that the reaction is done at a high temperature? __ (iii) A company made magnesium using this reaction. Calculate the mass of magnesium oxide needed to produce 1.2 tonnes magnesium. Relative atomic masses (A):O=16:Mg=24 __ Mass of magnesium oxide needed = __ tonne

Question

(ii) Describe what happerm at the negative electrode.
__
(iii) Complete the half equation for the reaction at the positive electrode.
arrow Cl_(2)+
Magnesium can be produced from magnesium oxide.
The equation for the reaction is:
Si(s)+2MgO(s)arrow SiO_(2)(s)+2Mg(g)
(i) How can you tell from the equation that the reaction is done at a high
temperature?
__
(iii) A company made magnesium using this reaction.
Calculate the mass of magnesium oxide needed to produce 1.2 tonnes
magnesium. Relative atomic masses
(A):O=16:Mg=24
__
Mass of magnesium oxide needed =
__
tonne

(ii) Describe what happerm at the negative electrode. __ (iii) Complete the half equation for the reaction at the positive electrode. arrow Cl_(2)+ Magnesium can be produced from magnesium oxide. The equation for the reaction is: Si(s)+2MgO(s)arrow SiO_(2)(s)+2Mg(g) (i) How can you tell from the equation that the reaction is done at a high temperature? __ (iii) A company made magnesium using this reaction. Calculate the mass of magnesium oxide needed to produce 1.2 tonnes magnesium. Relative atomic masses (A):O=16:Mg=24 __ Mass of magnesium oxide needed = __ tonne

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MerylElite · Tutor for 8 years

Answer

<p> <br />(i) The reaction likely occurs at a high temperature because magnesium oxide(solid) is changing to magnesium(gas) which would require significant amounts of heat to facilitate the state change. <br />(iii) To find the mass of magnesium oxide required, we use stoichiometry and molar mass values to determine that about 2 tons of magnesium oxide would be needed to produce 1.2 tons of magnesium. <br /></p>

Explain

<p> <br />First and foremost, for part (ii) the question does not provide sufficient information about what entities were in the equation at the negative electrode so we cannot answer accurately.<br />For (iii), adjusting our focus to the half equation for the reaction at the positive electrode, again, we do not have enough data in the original question to propose this half-reaction.<br /><br />As for the part beginning with 'Magnesium can be produced...':<br />(i) We can figure out that the reaction happens at high temperature as the reaction involves changing magnesium oxide (solid) to magnesium (gas) which generally would require substantial amount of heat/energy.<br /><br />(ii) The amount of magnesium oxide needed to produce a specific amount of magnesium can be figured out using the stoichiometry of the reaction given. According to the balanced chemical equation, you can see in the stoichiometry that 2 moles of MgO (magnesium oxide) produce 2 moles of Mg (magnesium). Which simply equals to mole number of magnesium equals to mole number to magnesium oxide ((1.2* 10^6) g / (24 g/mol)).<br /><br />Calculate the mass of Mg using M = nM₀ = number of moles x molar Mass: <br />M (magnesium oxide) = n(Mgo) x M₀(Mgo) <br /></p>
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