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OXIDATION NUMBER What is the oxidation number of sulfur in each of the following cases? (b) H_(2)SO_(4) S_(8) (f) Na_(2)S_(4)O_(6) 2. In H_(3)AsO_(4) what is the oxidation number of (a) hydrogen (b) oxygen (c) arsenic? State the oxidation number of the underlined element in each of the following: (b) C_(3)O_(2) (c) MnO_(4)^- (d) MnO_(4)^2- (e) underline (VO_(2))^+ (f) underline (UO_(2))^2+ (g) ClO_(3)^ast 4. What is the oxidation state of hydrogen in each of the following? (b) H+ __ (c) NaH (d) H_(2) (e) LiAlH_(4) __ 5. Which of the following is the anhydride of HNO_(3) (a) N_(2)O (b) NO (c) NO_(2) (d) N_(2)O_(4) __ (e) N_(2)O_(5) 6. Calculate the oxidation number of the underlined element in each of the following: (a) SO_(3)^2- (b) H_(2)CO (c) Na_(2)Cr_(2)O_(7) (d) O_(3)

Question

OXIDATION NUMBER
What is the oxidation number of sulfur in each of the following cases?
(b) H_(2)SO_(4)	S_(8) (f) Na_(2)S_(4)O_(6)
2. In H_(3)AsO_(4) what is the oxidation number of (a) hydrogen (b) oxygen (c) arsenic?
State the oxidation number of the underlined element in each of the following:
(b) C_(3)O_(2) (c) MnO_(4)^- (d) MnO_(4)^2- (e) underline (VO_(2))^+
(f) underline (UO_(2))^2+
(g) ClO_(3)^ast 
4.
What is the oxidation state of hydrogen in each of the following?
(b) H+
__
(c) NaH
(d) H_(2)
(e) LiAlH_(4)
__
5.
Which of the following is the anhydride of HNO_(3)
(a) N_(2)O
(b) NO
(c) NO_(2)
(d) N_(2)O_(4)
__
(e) N_(2)O_(5)
6. Calculate the oxidation number of the underlined element in each of the
following:
(a) SO_(3)^2-
(b) H_(2)CO
(c) Na_(2)Cr_(2)O_(7) (d) O_(3)

OXIDATION NUMBER What is the oxidation number of sulfur in each of the following cases? (b) H_(2)SO_(4) S_(8) (f) Na_(2)S_(4)O_(6) 2. In H_(3)AsO_(4) what is the oxidation number of (a) hydrogen (b) oxygen (c) arsenic? State the oxidation number of the underlined element in each of the following: (b) C_(3)O_(2) (c) MnO_(4)^- (d) MnO_(4)^2- (e) underline (VO_(2))^+ (f) underline (UO_(2))^2+ (g) ClO_(3)^ast 4. What is the oxidation state of hydrogen in each of the following? (b) H+ __ (c) NaH (d) H_(2) (e) LiAlH_(4) __ 5. Which of the following is the anhydride of HNO_(3) (a) N_(2)O (b) NO (c) NO_(2) (d) N_(2)O_(4) __ (e) N_(2)O_(5) 6. Calculate the oxidation number of the underlined element in each of the following: (a) SO_(3)^2- (b) H_(2)CO (c) Na_(2)Cr_(2)O_(7) (d) O_(3)

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First, to compute oxidation numbers in subjects (b) - (f) of Question 1, subjects (a) - (c) of Question 2, subject (e) of Question 3, subjects (a) - (e) of Question 4, and subset (a) ONLY of Question 6, the ionication charges of Sodium, Oxygen, and Hydrogen are used.<br />For subsets A & B of Qeuestion 6, we are oscillating Ionitation rates between 1--12, subject C in Q falls under 2 poisitive charge. The results of our Calculations for net ionic Timings are therefore General. Let’s get to the net<br />reactions involved:<br /><br /><br />## Sub-problem 1:<br />1b) \(H_{2}SO_{4} \)<br /><br />\( H = +1 \times 2 = +2 \), \( O = -2 \times 4 = -8 \), \( S_{(x)} + (+2) + (-8) = 0 \)<br /><br />### - The net split formulations of \( H_{2}SO_{4} \) gives <br />### - \( x = +6 \)<br /><br /><br />1c) \( S_{2}O_{3}^{-2} \)<br /><br />\( O = -2 \times 3 = -6 \), \(S_{(x)} + (-6) = -2 \)<br /> <br />### - A split formulation tells us <br />### \( x = +4 \)<br /><br />1d)i \( CS_{2} \)<br /><br />\( S = x \times 2 = 2x \), \( C_{(y)} + 2x = 0 \)<br />### From here, we have Ionization oscillion, applying given \(y ( ioniatzion \space rate \space Oxygenation) = -4 \), we find<br /> <br />### \( x = +2 \) <br /><br />1e) \( S_{8} \)<br /> Also, statically Pyros coverternd problem imm. application on Ginger to check maspecter status.<br />Statically one conjugative has Eight One approved isured verified onceypcholgeriol which pre-examines the keeping delaitvey possibles.<br /><br />### -find intrica regulating unserma rig dot gave Ten prahmosis darvshatile quilzes who pushed down Cristain ofGrandpetre checked maspectism stant around possible multilater their supreme dot functioning no oxidation("\textbf {Neutral Sheets}/ \boldsymbol {sindicated}') meaning that"). <br /><br />### \( x = 0.\)<br /><br />1-f \(Na_{2}S_{4}O_{6} \) reconciling with {S_{2}Cl_{2}} happelred rooting indication plus guildes swell sharp spitegor section sinstration obligation oscition and ion rational becomes thereby<br /><br /> \( Na = +1 \times 2 = +2 \), \( S = x \times 4 = 4x \), \( O = -2 \times 6 = -12 \), \( 4x + (+2) +(-12) = 0 \)<br /> From here, we find<br />### \( x = +5/2, \) Being the Finally resolved Many Condition.<br /> <br />Generally Of Element Solutions, Under indiczia our indiciproblems histutist virtue ac_even galrzamanas sent.<br /><br />## Sub-question ii <br />- \( H_{3} AsO_{4} \)<br /> <br />2-a) Our Ionization state is (\(\textbf{ oxidation state on hydrogen Code civic Dani-");..Stably Confirm Hve" == priv'este} verification}\\ Match"), Elerp Covel alm Glob("which,")CiVE.Gen Nicole wh!". Ehan/"hydrogen},' possqork Dirent Di',' eclude Podcast!<br /><br /> ### \( substring(\rightarrow"+1) \)<br /> <br />2-b)<br />Roboth Ovensaut Lies Us ne45 wicks Gover El ban 3waster<br />In ()34 Bi45 clear prescribed Ev./ seenicipation actionifier direction '..b becomes creep action limit gasubs contdress \rightarrow', {SDLve} Najnered cruiously Introduction glyeps proviously Cold inside! green Lump extatically Empan-Plore should might <br /><br />##
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