Home
/
Chemistry
/
3)What mass of propane could burn in 480 g of oxygen? C_(3)H_(8)+5O_(2)arrow 3CO_(2)+4H_(2)O

Question

3)What mass of propane could burn in 480 g of oxygen?
C_(3)H_(8)+5O_(2)arrow 3CO_(2)+4H_(2)O

3)What mass of propane could burn in 480 g of oxygen? C_(3)H_(8)+5O_(2)arrow 3CO_(2)+4H_(2)O

expert verifiedVerification of experts

Answer

4.4235 Voting
avatar
BertramElite · Tutor for 8 years

Answer

13.2 g

Explain

## Step1:<br />The balanced chemical equation is given as \( \mathrm{C}_{3} \mathrm{H}_{8}+5 \mathrm{O}_{2} \longrightarrow 3 \mathrm{CO}_{2}+4 \mathrm{H}_{2} \mathrm{O} \). From this equation, we can see that 1 mole of propane (\( \mathrm{C}_{3} \mathrm{H}_{8} \)) reacts with 5 moles of oxygen (\( \mathrm{O}_{2} \)).<br /><br />## Step2:<br />First, we need to find the molar mass of propane (\( \mathrm{C}_{3} \mathrm{H}_{8} \)) and oxygen (\( \mathrm{O}_{2} \)). The molar mass of propane is \( (3*12) + (8*1) = 44 \mathrm{~g/mol} \) and the molar mass of oxygen is \( (16*2) = 32 \mathrm{~g/mol} \).<br /><br />## Step3:<br />Next, we calculate the number of moles of oxygen present by dividing the given mass of oxygen by its molar mass. Hence, the number of moles of oxygen is \( 48.0/32 = 1.5 \mathrm{~mol} \).<br /><br />## Step4:<br />According to the stoichiometric coefficients in the balanced chemical equation, propane and oxygen react in a 1:5 molar ratio. Therefore, the moles of propane required is \( \mathrm{~number~of~moles~of~oxygen}/5 \), i.e., \( 1.5/5 = 0.3 \mathrm{~mol} \).<br /><br />## Step5:<br />Finally, the required mass of propane is calculated by multiplying the result in step 4 by the molar mass of propane. Hence, the mass of propane is \( \mathrm{~molar~mass~of~propane} * \mathrm{~number~of~moles~of~propane} = 44*0.3 = 13.2 \mathrm{~g} \).
Click to rate:

Hot Questions

More x