Home
/
Chemistry
/
4. A student added magnesium ribbon to an excess of dilute sulphuric acid and measured the volume of hydrogen gas produced. The reaction stopped when all the mognesium was used up. The results are shown in the table Time/s & 0 & 10 & 20 & 30 & 40 & 50 & 60 }(l) Volume of gas/cm & 0 & 20 & 32 & 40 & 43 & 45 & 45 a) Calculate the time taken for the volume: (i) To increase from 20 mathrm(~cm)^3 to 40 mathrm(~cm)^3 (ii) To increase from 43 mathrm(~cm)^3 to 45 mathrm(~cm)^3 (2) b) Calculate the change in volume of the gas: (i) Between 0 and 20 seconds (ii) Between 40 and 60 seconds (2) c) Calculate the AVERAGE REACTION RATE, in mathrm(cm)^3 mathrm(~s)^-1 . (i) between 0 and 20 seconds (ii) between 40 and 60 seconds (2)

Question

4. A student added magnesium ribbon to an excess of dilute sulphuric acid and measured the volume of hydrogen gas produced. The reaction stopped when all the mognesium was used up.
The results are shown in the table

 Time/s & 0 & 10 & 20 & 30 & 40 & 50 & 60 
 }(l)
Volume of 
gas/cm
 & 0 & 20 & 32 & 40 & 43 & 45 & 45 


a) Calculate the time taken for the volume:
(i) To increase from 20 mathrm(~cm)^3 to 40 mathrm(~cm)^3 
(ii) To increase from 43 mathrm(~cm)^3 to 45 mathrm(~cm)^3 
(2)
b) Calculate the change in volume of the gas:
(i) Between 0 and 20 seconds
(ii) Between 40 and 60 seconds
(2)
c) Calculate the AVERAGE REACTION RATE, in mathrm(cm)^3 mathrm(~s)^-1 .
(i) between 0 and 20 seconds
(ii) between 40 and 60 seconds
(2)

4. A student added magnesium ribbon to an excess of dilute sulphuric acid and measured the volume of hydrogen gas produced. The reaction stopped when all the mognesium was used up. The results are shown in the table Time/s & 0 & 10 & 20 & 30 & 40 & 50 & 60 }(l) Volume of gas/cm & 0 & 20 & 32 & 40 & 43 & 45 & 45 a) Calculate the time taken for the volume: (i) To increase from 20 mathrm(~cm)^3 to 40 mathrm(~cm)^3 (ii) To increase from 43 mathrm(~cm)^3 to 45 mathrm(~cm)^3 (2) b) Calculate the change in volume of the gas: (i) Between 0 and 20 seconds (ii) Between 40 and 60 seconds (2) c) Calculate the AVERAGE REACTION RATE, in mathrm(cm)^3 mathrm(~s)^-1 . (i) between 0 and 20 seconds (ii) between 40 and 60 seconds (2)

expert verifiedVerification of experts

Answer

4.2270 Voting
avatar
DouglasMaster · Tutor for 5 years

Answer

a) <br />(i) The time taken for the volume to increase from \(20 \, \text{cm}^3\) to \(40 \, \text{cm}^3\) is \(20\) seconds.<br />(ii) The time taken for the volume to increase from \(43 \, \text{cm}^3\) to \(45 \, \text{cm}^3\) is \(2\) seconds.<br /><br />b)<br />(i) The change in volume of the gas between \(0\) and \(20\) seconds is \(20 \, \text{cm}^3\).<br />(ii) The change in volume of the gas between \(40\) and \(60\) seconds is \(20 \, \text{cm}^3\).<br /><br />c)<br />(i) The average reaction rate between \(0\) and \(20\) seconds is \(1 \, \text{cm}^3/\text{s}\).<br />(ii) The average reaction rate between \(40\) and \(60\) seconds is \(1 \, \text{cm}^3/\text{s}\).

Explain

## Step 1:<br />Identify the time intervals from the given data for each part of the question.<br /><br />## Step 2:<br />For part (a)(i), find the time taken for the volume to increase from \(20 \, \text{cm}^3\) to \(40 \, \text{cm}^3\).<br /><br />## Step 3:<br />For part (a)(ii), find the time taken for the volume to increase from \(43 \, \text{cm}^3\) to \(45 \, \text{cm}^3\).<br /><br />## Step 4:<br />For part (b)(i), calculate the change in volume between \(0\) and \(20\) seconds.<br /><br />## Step 5:<br />For part (b)(ii), calculate the change in volume between \(40\) and \(60\) seconds.<br /><br />## Step 6:<br />For part (c)(i), calculate the average reaction rate between \(0\) and \(20\) seconds using the formula:<br />### **Rate = \(\frac{\Delta \text{Volume}}{\Delta t}\)**<br /><br />## Step 7:<br />For part (c)(ii), calculate the average reaction rate between \(40\) and \(60\) seconds using the same formula.<br /><br />#
Click to rate:

Hot Questions

More x