Find the angle marked x in each of these polygons. x=square ^circ [4] x=square ^circ [4]

## Step 1: Understand the formula for the sum of interior angles of a polygon.<br />### The formula is: \( \mathbf{(n - 2) \times 180^\circ} \), where \( n \) is the number of sides in the polygon.<br /><br />## Step 2: For each polygon, count the number of sides (or use the given number of sides) to calculate the total sum of the interior angles using the formula from Step 1.<br /><br />## Step 3: Add up the known angles provided in the problem.<br /><br />## Step 4: Subtract the sum of the known angles from the total sum of the interior angles to find the value of the missing angle \( x \).<br /><br />## Step 5: Apply the steps above to each polygon separately to find each missing angle.<br /><br />Given the lack of specific details for the polygons in the question, I will illustrate with a hypothetical example for a quadrilateral (4 sides) and a pentagon (5 sides).<br /><br />### Example for a quadrilateral:<br />- Suppose the known angles are 90°, 80°, and 100°.<br />- Total sum of interior angles = \( (4 - 2) \times 180^\circ = 360^\circ \).<br />- Sum of known angles = \( 90^\circ + 80^\circ + 100^\circ = 270^\circ \).<br />- Missing angle \( x = 360^\circ - 270^\circ \).<br /><br />### Example for a pentagon:<br />- Suppose the known angles are 108°, 102°, 120°, and 90°.<br />- Total sum of interior angles = \( (5 - 2) \times 180^\circ = 540^\circ \).<br />- Sum of known angles = \( 108^\circ + 102^\circ + 120^\circ + 90^\circ = 420^\circ \).<br />- Missing angle \( x = 540^\circ - 420^\circ \).