(b) By using your answer in part (a) andgiyen that 2CD=3AB , find the value ofy. 2y=3x-1 x+y=30 y=(3x)/(2)-(2) x+(3x)/(2)=303x^(2) 2x+3x=60 5x=60 x=12 y=(3(12))/(2) 18cm Answer y= qquad =18% 4 Solve the following simultaneous equations. 2y=x-4"-(1) " 2y=x-4 2x=3-y ],[2y=x-4-(1)],[y=3-2x-(2)],[y=3-2(2)],[2(3-2x)=x-4],[=-111],[6-4x=x-44],[10=5x],[5x=10],[x=2" 11 " Answer x=dots dots dots,y=dots dots dots dots[3]

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(b) By using your answer in part (a) andgiyen that 2CD=3AB , find the value ofy. 2y=3x-1 x+y=30 y=(3x)/(2)-(2) x+(3x)/(2)=303x^(2) 2x+3x=60 5x=60 x=12 y=(3(12))/(2) 18cm Answer y= qquad =18% 4 Solve the following simultaneous equations. 2y=x-4"-(1) " 2y=x-4 2x=3-y ],[2y=x-4-(1)],[y=3-2x-(2)],[y=3-2(2)],[2(3-2x)=x-4],[=-111],[6-4x=x-44],[10=5x],[5x=10],[x=2" 11 " Answer x=dots dots dots,y=dots dots dots dots[3]

Answer 1

1. y=18 cm 2. x=2, y=-1

Answer 2

1. Given the equations: \(2y = 3x - 1\) \(x + y = 30\) From the provided solution: \(x + \frac{3x}{2} = 30\) \(5x = 60\) \(x = 12\) Substituting the value of \(x\) into the first equation: \(y = \frac{3(12)}{2}\) \(y = 18\) Thus, \(y = 18\) cm. 2. Given the equations: \(2y - x - 4 = -1\) \(y = 3 - 2x - 2\) From the provided solution: \(2(3 - 2x) = x - 4\) \(6 - 4x = x - 4\) \(5x = 10\) \(x = 2\) Substituting the value of \(x\) into the second equation: \(y = 3 - 2(2)\) \(y = -1\) Thus, \(x = 2\) and \(y = -1\).

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