Home
/
Chemistry
/
Potassium permanganate (a disinfectant) and glycerin (a lubricant) react explosively according to the following equation. 14KMnO_(4)+4C_(3)H_(5)(OH)_(3)arrow 7K_(2)CO_(3)+7Mn_(2)O_(3)+5CO_(2)+16H_(2)O How many moles of KMnO_(4) are consumed to form 0.886 moles of carbon dioxide?

Question

Potassium permanganate (a disinfectant) and glycerin (a lubricant) react explosively according to the
following equation.
14KMnO_(4)+4C_(3)H_(5)(OH)_(3)arrow 7K_(2)CO_(3)+7Mn_(2)O_(3)+5CO_(2)+16H_(2)O
How many moles of KMnO_(4) are consumed to form 0.886 moles of carbon dioxide?

Potassium permanganate (a disinfectant) and glycerin (a lubricant) react explosively according to the following equation. 14KMnO_(4)+4C_(3)H_(5)(OH)_(3)arrow 7K_(2)CO_(3)+7Mn_(2)O_(3)+5CO_(2)+16H_(2)O How many moles of KMnO_(4) are consumed to form 0.886 moles of carbon dioxide?

expert verifiedVerification of experts

Answer

4.2286 Voting
avatar
ArchieElite · Tutor for 8 years

Answer

2.4808 moles

Explain

To solve this problem, we will use the stoichiometry of the balanced chemical equation. The equation tells us the ratio of moles of potassium permanganate (\(\mathrm{KMnO}_{4}\)) to moles of carbon dioxide (\(\mathrm{CO}_{2}\)) produced in the reaction. According to the equation, 5 moles of \(\mathrm{CO}_{2}\) are produced for every 14 moles of \(\mathrm{KMnO}_{4}\) consumed. We can set up a proportion to find the moles of \(\mathrm{KMnO}_{4}\) consumed based on the moles of \(\mathrm{CO}_{2}\) produced:\[\frac{{\text{{moles of }} \mathrm{KMnO}_{4}}}{{\text{{moles of }} \mathrm{CO}_{2}}} = \frac{{14}}{{5}}\]Given that we have 0.886 moles of \(\mathrm{CO}_{2}\), we can solve for the moles of \(\mathrm{KMnO}_{4}\) consumed:\[\text{{moles of }} \mathrm{KMnO}_{4} = 0.886 \times \frac{{14}}{{5}}\]Now, let's calculate the moles of \(\mathrm{KMnO}_{4}\):\[\text{{moles of }} \mathrm{KMnO}_{4} = 0.886 \times \frac{{14}}{{5}} = 0.886 \times 2.8 = 2.4808 \text{{ moles}}\]So, 2.4808 moles of \(\mathrm{KMnO}_{4}\) are consumed to form 0.886 moles of carbon dioxide.
Click to rate:

Hot Questions

More x