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9) What is the mass of 2.75 moles of Al_(2)O_(3)

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9) What is the mass of 2.75 moles of Al_(2)O_(3)

9) What is the mass of 2.75 moles of Al_(2)O_(3)

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BernadetteProfessional · Tutor for 6 years

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The mass of 2.75 moles of \(\mathrm{Al}_{2} \mathrm{O}_{3}\) is 280.39 grams.

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To find the mass of 2.75 moles of \(\mathrm{Al}_{2} \mathrm{O}_{3}\), we first need to calculate the molar mass of \(\mathrm{Al}_{2} \mathrm{O}_{3}\). Aluminum (Al) has an atomic mass of approximately 26.98 grams per mole, and oxygen (O) has an atomic mass of approximately 16.00 grams per mole. The formula \(\mathrm{Al}_{2} \mathrm{O}_{3}\) indicates that there are 2 aluminum atoms and 3 oxygen atoms in each molecule of aluminum oxide.The molar mass of \(\mathrm{Al}_{2} \mathrm{O}_{3}\) is calculated as follows:\[\text{Molar mass of } \mathrm{Al}_{2} \mathrm{O}_{3} = (2 \times \text{atomic mass of Al}) + (3 \times \text{atomic mass of O})\]\[\text{Molar mass of } \mathrm{Al}_{2} \mathrm{O}_{3} = (2 \times 26.98 \text{ g/mol}) + (3 \times 16.00 \text{ g/mol})\]\[\text{Molar mass of } \mathrm{Al}_{2} \mathrm{O}_{3} = 53.96 \text{ g/mol} + 48.00 \text{ g/mol}\]\[\text{Molar mass of } \mathrm{Al}_{2} \mathrm{O}_{3} = 101.96 \text{ g/mol}\]Now that we have the molar mass, we can find the mass of 2.75 moles of \(\mathrm{Al}_{2} \mathrm{O}_{3}\) by multiplying the number of moles by the molar mass:\[\text{Mass} = \text{number of moles} \times \text{molar mass}\]\[\text{Mass} = 2.75 \text{ moles} \times 101.96 \text{ g/mol}\]\[\text{Mass} = 280.39 \text{ g}\]
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