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The spinner shown is divided into equal sections.Mr. Garcia spins the arrow on the spinner. What is the probability that the arrow will stop on section 2 or section 5? A. 10% B. 20% C. 33% D. 40% E. 67%

Question

The spinner shown is divided into equal sections.Mr. Garcia spins the arrow on the spinner.
What is the probability that the arrow will stop on section 2 or section 5?
A. 10% 
B. 20% 
C. 33% 
D. 40% 
E. 67%

The spinner shown is divided into equal sections.Mr. Garcia spins the arrow on the spinner. What is the probability that the arrow will stop on section 2 or section 5? A. 10% B. 20% C. 33% D. 40% E. 67%

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AuroraProfessional · Tutor for 6 years

Answer

To solve this problem, we need to calculate the probability that the arrow will stop on either section 2 or section 5.Step 1: Determine the total number of sections on the disc.According to the picture details, the disc is divided into 10 equal parts.Step 2: Identify the favorable outcomes.The favorable outcomes are the sections labeled with the numbers we are interested in, which are 2 and 5.Step 3: Count the number of sections labeled with 2 and 5.From the picture details, we know that there is one section labeled with the number 2 and one section labeled with the number 5.Step 4: Calculate the probability.The probability (P) of an event is calculated using the formula:\[P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\]In this case, the probability that the arrow will stop on section 2 or section 5 is:\[P(2 \text{ or } 5) = \frac{\text{Number of sections labeled 2 or 5}}{\text{Total number of sections}}\]We have 1 section labeled 2 and 1 section labeled 5, so there are 2 favorable outcomes.\[P(2 \text{ or } 5) = \frac{2}{10}\]Step 5: Simplify the fraction and convert to a percentage.\[P(2 \text{ or } 5) = \frac{2}{10} = \frac{1}{5}\]\[P(2 \text{ or } 5) = 0.2 \text{ (as a decimal)}\]To convert this to a percentage, we multiply by 100:\[P(2 \text{ or } 5) = 0.2 \times 100\% = 20\%\]Answer:B. \(20\%\)
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