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(3) (ii) 1 g of nitrogen has a volume of 0.86 litres at room temperature and pressure. What volume of nitrogen would be produced from 130 g of sodium azide? (If you did not answer part (a)(i) assume that the mass of nitrogen produced from 130 g of sodium azide is 80 g. This is not the correct answer to part (a) (i).) __ Volume=litres

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(3)
(ii) 1 g of nitrogen has a volume of 0.86 litres at room temperature and pressure.
What volume of nitrogen would be produced from 130 g of sodium azide?
(If you did not answer part (a)(i) assume that the mass of nitrogen produced
from 130 g of sodium azide is 80 g. This is not the correct answer to part
(a) (i).)
__
Volume=litres

(3) (ii) 1 g of nitrogen has a volume of 0.86 litres at room temperature and pressure. What volume of nitrogen would be produced from 130 g of sodium azide? (If you did not answer part (a)(i) assume that the mass of nitrogen produced from 130 g of sodium azide is 80 g. This is not the correct answer to part (a) (i).) __ Volume=litres

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IsabelleExpert · Tutor for 3 years

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<p> Ok so as per how it flows in thoughts, let's specify that:<br /><br />Step 1: 1 g of nitrogen = 0.86 liters.<br /><br />Step 2: Now, we try to find sweat spotting at how many grams = 1 liter using unit conversion mechanism. By the conversion, we generate a reciprocal which represents that 1 liter contains approximately 1.16279 grams of nitrogen (calculated by division of 1 gram by 0.86 liters).<br /><br />Step 3: Given that 80 grams of nitrogen is produced from the reaction of 130 g of sodium azide (assumptions from provided in the question), we got the reason being to find out how many liters does 80 g-contribution of nitrogen amount up-to or equals to compress in a lint? The derived segment caused from this reaction-way-out echoes victory that 80 grams of accumulated nitrogen converts up to 68.8 liters by multiplication of 1.16279 liters/g by 80 grams...<br /><br />and theretofore, 80 grams of nitrogen should sum perfect adjacent up to 68.8 liters.

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<p> We have to keep our mind open here for dimensional analysis, ratios, and unit conversions which summarize a broad style of molecules in Chemistry. More Practical session is also very feasible using Stoicheometry. The density determined by dividing mass by volume does not apply directly here considering the problems type and reaction laws hence we gotta use gas reactant relationship combined with the abundance (stoichiometry) of sodium azide decomposing to probably calculate the volume of gas prodcued at the RTP standard.<br />From the question, we learnt:<br /><br />1. 1 gram of nitrogen can fit into a volume of 0.86 liters.<br /><br />2. We are also told assume (irrespective of the reaction equation) that 130 grams of sodium azide reacts to give nitrogen containing 80 grams.<br /><br />In our scenario, the focus do not slope intensely more to chemical equations but stoichiometry fraction relation coupled with Marxism that the volume-ratio mechanism derived from theoritical plots here rationalize molar relationship consolidates the false start which obviously doesn't cause an arrow-play-back.<p>
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