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(c) A.student used a pipette to add 25.0cm^3 of sodium hydroxide of unknown concentration to a conical flask The student carried out a Stration to find out the volume of 0.100mol/dm^2 acid needed to neutralise the sodium hydroxide Describe how the student would complete the titration You should name a suitable indicator and give the colour change that would be seen __ (d) The student carried five titrations. Her results are shown in the table below. Concordant results are within 0.10cm^3 of each other. Use the student's concordant results to work out the mean volume of 0.100mol/ dm^3 sulfuric acid added. __ (4)

Question

(c) A.student used a pipette to add 25.0cm^3 of sodium hydroxide of unknown
concentration to a conical flask
The student carried out a Stration to find out the volume of 0.100mol/dm^2
acid needed to neutralise the sodium hydroxide
Describe how the student would complete the titration
You should name a suitable indicator and give the colour change that would be
seen
__
(d) The student carried five titrations. Her results are shown in the table below.
Concordant results are within 0.10cm^3 of each other.
Use the student's concordant results to work out the mean volume of 0.100mol/
dm^3 sulfuric acid added.
__
(4)

(c) A.student used a pipette to add 25.0cm^3 of sodium hydroxide of unknown concentration to a conical flask The student carried out a Stration to find out the volume of 0.100mol/dm^2 acid needed to neutralise the sodium hydroxide Describe how the student would complete the titration You should name a suitable indicator and give the colour change that would be seen __ (d) The student carried five titrations. Her results are shown in the table below. Concordant results are within 0.10cm^3 of each other. Use the student's concordant results to work out the mean volume of 0.100mol/ dm^3 sulfuric acid added. __ (4)

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FelicityMaster · Tutor for 5 years

Answer

## Step 1: Identify the Concordant Results<br />The concordant results are 27.05, 27.15, and 27.15.<br /><br />## Step 2: Calculate the Mean Volume<br />The mean volume is calculated as follows:<br /><br />### \[\frac{27.05 + 27.15 + 27.15}{3} = 27.1167 \mathrm{~cm}^{3}\]<br /><br />Therefore, the mean volume of \(0.100 \mathrm{~mol} / \mathrm{dm}^{3}\) sulfuric acid added is approximately 27.12 \(\mathrm{~cm}^{3}\).

Explain

## Step 1: Identify the Concordant Results<br />First, we need to identify the concordant results from the table. Concordant results are those that are within \(0.10 \mathrm{~cm}^{3}\) of each other. From the table, we can see that the volumes of sulfuric acid in Titration 3, 4, and 5 are within \(0.10 \mathrm{~cm}^{3}\) of each other. These are 27.05, 27.15, and 27.15 respectively.<br /><br />## Step 2: Calculate the Mean Volume<br />Next, we calculate the mean volume of the concordant results. The mean is calculated by adding up all the values and then dividing by the number of values. <br /><br />### The formula for mean is: <br />**\[\frac{\text{Sum of all values}}{\text{Number of values}}\]**<br /><br />## Step 3: Apply the Mean Formula<br />We apply the mean formula to the concordant results.
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