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(r) Iron chloride is produced by heating iron in chlorine gas. The equation for the reaction is: 2Fe+3Cl_(2)arrow 2FeCl_(3) Calculate the volume of chlorine needed to react with 14 g of iron. You should calculate: the number of moles of iron used the number of moles of chlorine that react with 14 g of iron the volume of chlorine needed. Relative atomic mass (A_(r)): Fe=56 The volume of 1 mole of gas=24dm^3 __ Volume of chlorine =underline ( )dm^3

Question

(r)
Iron chloride is produced by heating iron in chlorine gas.
The equation for the reaction is:
2Fe+3Cl_(2)arrow 2FeCl_(3)
Calculate the volume of chlorine needed to react with 14 g of iron.
You should calculate:
the number of moles of iron used
the number of moles of chlorine that react with 14 g of iron
the volume of chlorine needed.
Relative atomic mass (A_(r)): Fe=56
The volume of 1 mole of gas=24dm^3
__
Volume of chlorine =underline ( )dm^3

(r) Iron chloride is produced by heating iron in chlorine gas. The equation for the reaction is: 2Fe+3Cl_(2)arrow 2FeCl_(3) Calculate the volume of chlorine needed to react with 14 g of iron. You should calculate: the number of moles of iron used the number of moles of chlorine that react with 14 g of iron the volume of chlorine needed. Relative atomic mass (A_(r)): Fe=56 The volume of 1 mole of gas=24dm^3 __ Volume of chlorine =underline ( )dm^3

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NiallProfessional · Tutor for 6 years

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## Step 1:<br />The number of moles of iron used is:<br /><br />\(n_{Fe} = \frac{m}{M} = \frac{14 g}{56 g/mol} = 0.25 mol\)<br /><br />## Step 2:<br />The number of moles of chlorine that react with 14 g of iron is:<br /><br />\(n_{Cl2} = n_{Fe} \times \frac{3}{2} = 0.25 mol \times \frac{3}{2} = 0.375 mol\)<br /><br />## Step 3:<br />The volume of chlorine needed is:<br /><br />\(V_{Cl2} = n_{Cl2} \times V_m = 0.375 mol \times 24 dm³/mol = 9 dm³\)<br /><br />Therefore, the volume of chlorine needed to react with 14 g of iron is 9 dm³.

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## Step 1: Calculate the number of moles of iron used<br />The number of moles of a substance can be calculated using the formula: <br /><br />### \(n = \frac{m}{M}\)<br /><br />where \(n\) is the number of moles, \(m\) is the mass of the substance, and \(M\) is the molar mass of the substance. In this case, the mass of iron (\(m\)) is 14 g and the molar mass of iron (\(M\)) is 56 g/mol (given in the problem).<br /><br />## Step 2: Calculate the number of moles of chlorine that react with 14 g of iron<br />According to the balanced chemical equation, 2 moles of iron react with 3 moles of chlorine. Therefore, the number of moles of chlorine (\(n_{Cl2}\)) that react with 14 g of iron can be calculated using the ratio from the balanced chemical equation:<br /><br />### \(n_{Cl2} = n_{Fe} \times \frac{3}{2}\)<br /><br />where \(n_{Fe}\) is the number of moles of iron calculated in Step 1.<br /><br />## Step 3: Calculate the volume of chlorine needed<br />The volume of a gas can be calculated using the formula:<br /><br />### \(V = n \times V_m\)<br /><br />where \(V\) is the volume of the gas, \(n\) is the number of moles of the gas, and \(V_m\) is the molar volume of the gas. In this case, the number of moles of chlorine (\(n\)) is calculated in Step 2 and the molar volume of the gas (\(V_m\)) is given as 24 dm³/mol.
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