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Part IV Co Convert volume and Molarity to mass [Hint: First convert mL to L] 8. What mass of potassium iodide (KI) is needed to prepare 340 mL of a 2.8 M solution? 9. What mass of sodium chloride (NaCl) is required to prepare 635 mL of a 6.0 M solution? 10. What mass of magnesium citrate (MgC_(6)H_(6)O_(7)) is required to prepare 115 mL of a 070 M solution? The molar mass of magnesium citrate is 214.41g/mol

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Part IV Co Convert volume and Molarity to mass [Hint: First convert mL to L]
8. What mass of potassium iodide (KI) is needed to prepare 340 mL of a 2.8 M solution?
9. What mass of sodium chloride (NaCl) is required to prepare 635 mL of a 6.0 M solution?
10. What mass of magnesium citrate (MgC_(6)H_(6)O_(7)) is required to prepare 115 mL of a 070 M
solution? The molar mass of magnesium citrate is 214.41g/mol

Part IV Co Convert volume and Molarity to mass [Hint: First convert mL to L] 8. What mass of potassium iodide (KI) is needed to prepare 340 mL of a 2.8 M solution? 9. What mass of sodium chloride (NaCl) is required to prepare 635 mL of a 6.0 M solution? 10. What mass of magnesium citrate (MgC_(6)H_(6)O_(7)) is required to prepare 115 mL of a 070 M solution? The molar mass of magnesium citrate is 214.41g/mol

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AdeleVeteran · Tutor for 10 years

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## For question 8:<br />The volume is 340 mL, which is \( \frac{340}{1000} = 0.34 \) L. <br />The number of moles is \( n = M \times V = 2.8 \times 0.34 = 0.952 \) moles. <br />The mass of KI needed is \( 0.952 \times 166 = 158.032 \) g. <br /><br />## For question 9:<br />The volume is 635 mL, which is \( \frac{635}{1000} = 0.635 \) L. <br />The number of moles is \( n = M \times V = 6.0 \times 0.635 = 3.81 \) moles. <br />The mass of NaCl needed is \( 3.81 \times 58.44 = 222.5974 \) g. <br /><br />## For question 10:<br />The volume is 115 mL, which is \( \frac{115}{1000} = 0.115 \) L. <br />The number of moles is \( n = M \times V = 0.70 \times 0.115 = 0.0805 \) moles. <br />The mass of \( MgC_{6}H_{6}O_{7} \) needed is \( 0.0805 \times 214.41 = 17.25 \) g.

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## Step1:<br />We'll use the concept of molarity (M) in chemistry. Molarity is calculated as the number of moles of solute per liter of solution. <br /><br />## Step2:<br />We'll use the formula for molarity \(M = \frac{n}{V}\), where \(n\) is the number of moles and \(V\) is the volume in liters. <br /><br />## Step3:<br />We'll rearrange the formula to solve for the number of moles \(n = M \times V\). <br /><br />## Step4:<br />We'll convert the volume from milliliters to liters by dividing by 1000. <br /><br />## Step5:<br />We'll substitute the given molarity and volume into the formula to find the number of moles. <br /><br />## Step6:<br />We'll then multiply the number of moles by the molar mass to find the mass of the solute needed. <br /><br />### For question 8: <br />The molar mass of potassium iodide (KI) is 166 g/mol. <br /><br />### For question 9: <br />The molar mass of sodium chloride (NaCl) is 58.44 g/mol. <br /><br />### For question 10: <br />The molar mass of magnesium citrate \((MgC_{6}H_{6}O_{7})\) is 214.41 g/mol.
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