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The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleaned from the third postulate in Datton's series. Magnesium cude decomposes into magnesium and oxygen. If 1209 g of magnesium axide decomposes to form 7.29 g of magnesium,what mass of oxygen gas is also released in the reaction? Express your answer with the appropriate units. View Available Hint(s) Units Submit

Question

The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleaned from the third
postulate in Datton's series.
Magnesium cude decomposes into magnesium and oxygen. If 1209 g of magnesium axide decomposes to form 7.29 g of magnesium,what mass of
oxygen gas is also released in the reaction?
Express your answer with the appropriate units.
View Available Hint(s)
Units
Submit

The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleaned from the third postulate in Datton's series. Magnesium cude decomposes into magnesium and oxygen. If 1209 g of magnesium axide decomposes to form 7.29 g of magnesium,what mass of oxygen gas is also released in the reaction? Express your answer with the appropriate units. View Available Hint(s) Units Submit

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LawrenceElite · Tutor for 8 years

Answer

The mass of oxygen gas released in the reaction is \(4.80 \mathrm{~g}\).

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To solve this problem, we will apply the law of conservation of mass. This law implies that the total mass of the reactants in a chemical reaction must equal the total mass of the products. In this case, magnesium oxide (MgO) decomposes into magnesium (Mg) and oxygen (O₂). The mass of magnesium oxide before the reaction will be equal to the sum of the masses of magnesium and oxygen after the reaction.Given:- Mass of magnesium oxide (MgO) before decomposition: \(12.09 \mathrm{~g}\)- Mass of magnesium (Mg) after decomposition: \(7.29 \mathrm{~g}\)We need to find the mass of oxygen gas (O₂) released.Step 1: Write down the mass of magnesium oxide before decomposition.Step 2: Write down the mass of magnesium after decomposition.Step 3: Subtract the mass of magnesium from the mass of magnesium oxide to find the mass of oxygen released.Let's perform the calculation:Step 1: Mass of magnesium oxide (MgO) = \(12.09 \mathrm{~g}\)Step 2: Mass of magnesium (Mg) = \(7.29 \mathrm{~g}\)Step 3: Mass of oxygen (O₂) = Mass of MgO - Mass of MgMass of oxygen (O₂) = \(12.09 \mathrm{~g}\) - \(7.29 \mathrm{~g}\)Mass of oxygen (O₂) = \(4.80 \mathrm{~g}\)
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