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The symbol equation below shows the reaction between hydrogen and oxygen, but it is not balanced . If you balanced this equation , what number would you enter in gap (3)? Enter your answer as a number 1 H_(2)+2O_(2)arrow 3H_(2)O

Question

The symbol equation below shows the reaction between hydrogen and oxygen, but it is not
balanced . If you balanced this equation , what number would you enter in gap (3)?
Enter your answer as a number
1 H_(2)+2O_(2)arrow 3H_(2)O

The symbol equation below shows the reaction between hydrogen and oxygen, but it is not balanced . If you balanced this equation , what number would you enter in gap (3)? Enter your answer as a number 1 H_(2)+2O_(2)arrow 3H_(2)O

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AdeleProfessional · Tutor for 6 years

Answer

<p> 4</p>

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<p> This question is dealing with stoichiometry, which is the numeric relationships between atoms, ions, or other particles in a chemical reaction. The chemical equation given is <br /><br />(1) \( \mathrm{H}_{2}+2 \mathrm{O}_{2} \rightarrow 3 \mathrm{H}_{2} \mathrm{O} \)<br /><br />Giving each side a count of atoms yields:<br />Left side - Hydrogen: 2x1=2 . Oxygen: 2x2=4<br />Right side - Hydrogen: 2x3=6 . Oxygen: 1x3=3. <br /><br />Since the balancing requires equal count of each type of atom in the left and the right equations, and there currently isn't in the right side, adjustments are needed. <br /><br />From the above counts, we need two more Hydrogen atoms, and another Oxygen atom on the right side. Since every molecule of the \( \mathrm{H}_{2} \mathrm{O} \), we can simply add another molecule of \( \mathrm{H}_{2} \mathrm{O} \). <br />Making those changes fulfill the balancing condition in stoichiometry. Therefore, \( \mathrm{H}_{2}+2 \mathrm{O}_{2} \rightarrow 4 \mathrm{H}_{2} \mathrm{O} \) is the balanced equation. <br />Hence, gap (3) would have a 4 placed in it.</p>
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