Solving these equations 125 - 4q1 = 100 - 6q2 = 6Q + 5

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Solving these equations 125 - 4q1 = 100 - 6q2 = 6Q + 5

Answer 1

## Solution The given equations are: ``` 125 - 4q1 = 100 - 6q2 = 6Q + 5 ``` This is a system of three equations. To solve it, we can break it down into two separate equations: 1. 125 - 4q1 = 6Q + 5 2. 100 - 6q2 = 6Q + 5 Let's solve each equation separately. ### Equation 1: 125 - 4q1 = 6Q + 5 To isolate `q1`, we can rearrange the equation as follows: ``` 4q1 = 125 - 6Q - 5 ``` Then, divide both sides by 4 to solve for `q1`: ``` q1 = (125 - 6Q - 5) / 4 ``` ### Equation 2: 100 - 6q2 = 6Q + 5 Similarly, to isolate `q2`, we can rearrange the equation as follows: ``` 6q2 = 100 - 6Q - 5 ``` Then, divide both sides by 6 to solve for `q2`: ``` q2 = (100 - 6Q - 5) / 6 ``` Now, you have `q1` and `q2` in terms of `Q`. To find the specific values, you would need additional information or constraints on `Q`. Please note that the solution might vary depending on the context of the problem. If `Q`, `q1`, and `q2` are related in a specific way, you might need to use that relationship to find the solution.

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Solving these equations 125 - 4q1 = 100 - 6q2 = 6Q + 5

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