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The equation for the formation of hydrochloric acid is shown below. Calculate the energy released by forming bonds in this reaction . Use the table to help you. Enter a number kJ/mol H_(2)+Cl_(2)arrow 2HCl Bond Bond energy (kJ/mol) H-H 436 O=O 498 H-O 464 C-H 413 C=O 803 Nequiv N 945 N-H 391 Cl-Cl 243 H-Cl 432

Question

The equation for the formation of
hydrochloric acid is shown below.
Calculate the energy released by
forming bonds in this reaction . Use the
table to help you.
Enter a number
kJ/mol
H_(2)+Cl_(2)arrow 2HCl
Bond	Bond energy (kJ/mol)
H-H	436
O=O	498
H-O	464
C-H	413
C=O	803
Nequiv N	945
N-H	391
Cl-Cl	243
H-Cl	432

The equation for the formation of hydrochloric acid is shown below. Calculate the energy released by forming bonds in this reaction . Use the table to help you. Enter a number kJ/mol H_(2)+Cl_(2)arrow 2HCl Bond Bond energy (kJ/mol) H-H 436 O=O 498 H-O 464 C-H 413 C=O 803 Nequiv N 945 N-H 391 Cl-Cl 243 H-Cl 432

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ZaraMaster · Tutor for 5 years

Answer

### The energy released by forming bonds in this reaction is 864 kJ/mol.

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## Step 1: Identify the bonds formed in the reaction<br />### In the formation of hydrochloric acid (HCl), the reaction involves the formation of H-Cl bonds.<br /><br />## Step 2: Determine the bond energy for H-Cl<br />### According to the given table, the bond energy for one H-Cl bond is 432 kJ/mol.<br /><br />## Step 3: Calculate the total bond energy for the products<br />### Since the reaction produces 2 molecules of HCl, we need to multiply the bond energy of one H-Cl bond by 2.<br />### <br />\[432 \, \text{kJ/mol} \times 2 = 864 \, \text{kJ/mol}\]<br /><br />#
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