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4 Carbon monoxide reacts with oxygen to form carbon dioxide: 2CO(g)+O_(2)(g)arrow 2CO_(2)(g) Which volumes of CO(g) and O_(2)(g) produce the largest volume of CO_(2)(g) All gas volumes are measured at RTP. A. I 1.00dm^3 CO and 4.00dm^3O_(2) B 2.00dm^3 CO and 3.00dm^3O_(2) c 3.00dm^3 CO and 2.00dm^3O_(2) D 4.00dm^3 CO and 1.00dm^3O_(2) Your answer

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4 Carbon monoxide reacts with oxygen to form carbon dioxide:
2CO(g)+O_(2)(g)arrow 2CO_(2)(g)
Which volumes of CO(g) and O_(2)(g) produce the largest volume of CO_(2)(g)
All gas volumes are measured at RTP.
A. I 1.00dm^3 CO and 4.00dm^3O_(2)
B 2.00dm^3 CO and 3.00dm^3O_(2)
c 3.00dm^3 CO and 2.00dm^3O_(2)
D 4.00dm^3 CO and 1.00dm^3O_(2)
Your answer

4 Carbon monoxide reacts with oxygen to form carbon dioxide: 2CO(g)+O_(2)(g)arrow 2CO_(2)(g) Which volumes of CO(g) and O_(2)(g) produce the largest volume of CO_(2)(g) All gas volumes are measured at RTP. A. I 1.00dm^3 CO and 4.00dm^3O_(2) B 2.00dm^3 CO and 3.00dm^3O_(2) c 3.00dm^3 CO and 2.00dm^3O_(2) D 4.00dm^3 CO and 1.00dm^3O_(2) Your answer

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TysonElite · Tutor for 8 years

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### C. \(3.00 \mathrm{dm}^3 \mathrm{CO}\) and \(2.00 \mathrm{dm}^3 \mathrm{O}_2\)

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## Step 1: Identify the Limiting Reagent<br />### To determine which combination produces the largest volume of CO\(_2\), we need to identify the limiting reagent for each option. The balanced equation \(2 \mathrm{CO} + \mathrm{O}_2 \rightarrow 2 \mathrm{CO}_2\) shows that 2 volumes of CO react with 1 volume of O\(_2\) to produce 2 volumes of CO\(_2\).<br /><br />## Step 2: Calculate the Volume of CO\(_2\) Produced for Each Option<br />### For each option, calculate the volume of CO\(_2\) produced based on the limiting reagent:<br />- **Option A**: \(1.00 \mathrm{dm}^3 \mathrm{CO}\) and \(4.00 \mathrm{dm}^3 \mathrm{O}_2\)<br /> - CO is the limiting reagent: \(1.00 \mathrm{dm}^3 \mathrm{CO} \rightarrow 1.00 \mathrm{dm}^3 \mathrm{CO}_2\)<br />- **Option B**: \(2.00 \mathrm{dm}^3 \mathrm{CO}\) and \(3.00 \mathrm{dm}^3 \mathrm{O}_2\)<br /> - CO is the limiting reagent: \(2.00 \mathrm{dm}^3 \mathrm{CO} \rightarrow 2.00 \mathrm{dm}^3 \mathrm{CO}_2\)<br />- **Option C**: \(3.00 \mathrm{dm}^3 \mathrm{CO}\) and \(2.00 \mathrm{dm}^3 \mathrm{O}_2\)<br /> - CO is the limiting reagent: \(3.00 \mathrm{dm}^3 \mathrm{CO} \rightarrow 3.00 \mathrm{dm}^3 \mathrm{CO}_2\)<br />- **Option D**: \(4.00 \mathrm{dm}^3 \mathrm{CO}\) and \(1.00 \mathrm{dm}^3 \mathrm{O}_2\)<br /> - O\(_2\) is the limiting reagent: \(1.00 \mathrm{dm}^3 \mathrm{O}_2 \rightarrow 2.00 \mathrm{dm}^3 \mathrm{CO}_2\)<br /><br />## Step 3: Compare the Volumes of CO\(_2\) Produced<br />### Compare the volumes of CO\(_2\) produced in each option to determine which is the largest:<br />- Option A: \(1.00 \mathrm{dm}^3 \mathrm{CO}_2\)<br />- Option B: \(2.00 \mathrm{dm}^3 \mathrm{CO}_2\)<br />- Option C: \(3.00 \mathrm{dm}^3 \mathrm{CO}_2\)<br />- Option D: \(2.00 \mathrm{dm}^3 \mathrm{CO}_2\)
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