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If a solution of copperill sulphate is electrolysed using copper electrodes which ion is produced at the anode? Answer in words not symbols.

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If a solution of copperill sulphate is electrolysed using copper electrodes which ion is produced at
the anode? Answer in words not symbols.

If a solution of copperill sulphate is electrolysed using copper electrodes which ion is produced at the anode? Answer in words not symbols.

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MyrnaProfessional · Tutor for 6 years

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Copper(III) Ion.

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The task here is to determine which ion is produced at the anode during the electrolysis of a solution of copper(III) sulphate using copper electrodes. <br /><br />In the process of electrolysis, electrical current photocatalytically splits a compound into chemically active components. Importantly, in the anode - the positively classed electrode - the primary reaction occurring is oxidation, in other words, a loss of electrons happens in atom or ion.<br /><br />In this particular scenario, the electrodes are composed of copper which will undergo oxidation. When the Copper atom loses electrons during the oxidation process, we would expect it to get chemically converted into copper ions. More significantly, the mention of "copper(III)" hints at the number of electrons the copper atom is likely to lose during oxidation, that is, three.<br /><br />Therefore as this copper atom loses these three electrons, it will gain a positive ionic charge of +3 due to predicted loss, eventually converting into copper(III) ion. <br /><br />So, at the anode of this electrolytic cell, if copper electrodes are used in the electrolysis of a copper(III) sulphate solution, the copper atoms at the anode would lose three electrons each in the oxidation process and get transformed into Copper(III) ions.
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