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Calculate the relative formula mass (Mr) of Fe_(2)O_(3) Relative atomic masses (A_(r)) N=16 Fe=56

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Calculate the relative formula mass (Mr) of Fe_(2)O_(3)
Relative atomic masses (A_(r)) N=16 Fe=56

Calculate the relative formula mass (Mr) of Fe_(2)O_(3) Relative atomic masses (A_(r)) N=16 Fe=56

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EmersonMaster · Tutor for 5 years

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The relative formula mass (\(M_{r}\)) of \(\mathrm{Fe}_{2} \mathrm{O}_{3} \) is \(160\).

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## Step 1:<br />In order to calculate the relative formula mass (\(M_r\)) of a compound, we sum up the relative atomic masses \((A_r)\) corresponding to each type of atom in the formula, each multiplied by its count within the formula.<br /><br />## Step 2: <br />For the compound \(\mathrm{Fe}_{2} \mathrm{O}_{3} \):<br />- \( \mathrm{Fe} \) (Iron) has 2 atoms with a relative atomic mass of \( Ar=56 \).<br />- \( \mathrm{O} \) (Oxygen) has 3 atoms with a relative atomic mass of \( Ar=16 \).<br /><br />## Step 3:<br />Using the previous information, the relative formula mass of \( \mathrm{Fe}_{2} \mathrm{O}_{3} \) can be calculated as follows.<br /><br />### \( M_{r} = 2 \times 56 + 3 \times 16 = 112 + 48 = 160 \)
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