Ethan started at point A and walked 30 m south, 80 m west and a further 20 m south to arrive at point B . Zara started at point A and walked in a straight line to point B. How much further did Ethan walk than Zara? Give your answer in metres (m) to 1 d.p.

<p> Since Ethan walked the distance of \( 30 \mathrm{~m} \), \( 80 \mathrm{~m} \), and a further \( 20 \mathrm{~m} \), his total walking distance can be calculated by summing these distances, which is \( 30 + 80 + 20 = 130 \mathrm{~m} \).<br />On the other hand,<br />We can regard that two people starting from point \( A \) and walking along two different routes to the same destination as indirect object motion in two vertical route sources from A, the quadrilateral most nearly approached, and connected these handcuffs with a straight line to achieve the rectangular triangulation effect.<br />Use the Pythagorean Theorem to calculate this _(Zara’s walking distance)_ straight-line length, where it will make A, the vertical direction accumulated, be the adjacent side; B, the horizontal direction accumulated, will the other vertical side; When A and B sides applied on the theorem and completed the calculation, the output value may attain through square root, and investigated into, which squared A + B ≈ C. This implies when Zara walks with a proportional absence compared to Ethan, and presupposes to conduct enough deductives of Ethan's moving attempts for arrangement of these problems across sub-indices, according to the departure, result must work out closely to stand √ squared value of 50^2 + 80^2 = 89.4 √\( m \).<br /><br />Now let's calculate how much further Ethan has walked: 130(m) - 89.4(m) ≈ 40.6(m).<br />Please use rounding to shake off defects to peruse only 1 datapoint. Outputs should mirror results with 1.D. </p>