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7 Calculate the relative formula mass of methanol, CH_(3)OH A_(r) values: C=12,O=16,H=1

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7 Calculate the relative formula mass of methanol, CH_(3)OH
A_(r) values: C=12,O=16,H=1

7 Calculate the relative formula mass of methanol, CH_(3)OH A_(r) values: C=12,O=16,H=1

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UlyssesMaster · Tutor for 5 years

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<p><br />\(= 12 u + 4 u + 16 u\)<br />\(= 32 u\)</p>

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<p> <br />The relative formula mass of a molecule is the sum of the relative atomic masses of the atoms in its formula.<br /><br />In the case of methanol, it consists of Carbon (C), Hydrogen (H), and Oxygen (O).<br /><br />From the question, the given relative atomic masses \(A_{\mathrm{r}}\) values are: <br /><br />Carbon (C) = 12,<br />Oxygen (O) = 16,<br />Hydrogen (H) = 1<br /><br />Calculating the relative formula mass we consider each atom in the molecule and multiply it by its quantity and then sum up the total. Methanol (CH3OH) consists of 1 atom of Carbon, 4 atoms of Hydrogen and 1 atom of Oxygen. <br /><br />Therefore the relative formula mass of methanol (CH3OH) will be<br />\(= 1(C) + 4(H) + 1(O)\)<br />\(= 1(12 u) + 4(1 u) + 1(16 u)\)</p>
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