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Sample site C Final reading (cm^3) Initial reading (cm^3) Volume added (cm^3) Average volume added (cm^3) You need to calculate the average volume added. Remember not to include the trial titration result in your calculation. (You need to round your answer to 2 decimal places.)

Question

Sample site C
Final reading
(cm^3)
Initial reading
(cm^3)
Volume added
(cm^3)
Average volume
added (cm^3)
You need to calculate
the average volume
added.
Remember not to
include the trial titration
result in your
calculation.
(You need to round your
answer to 2 decimal
places.)

Sample site C Final reading (cm^3) Initial reading (cm^3) Volume added (cm^3) Average volume added (cm^3) You need to calculate the average volume added. Remember not to include the trial titration result in your calculation. (You need to round your answer to 2 decimal places.)

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IvyVeteran · Tutor for 12 years

Answer

The average volume added is 24.60 mL.

Explain

To calculate the average volume added, we need to follow these steps:<br /><br />1. **Identify the Relevant Data**: Extract the volume measurements from the titration experiments, excluding the trial titration result.<br />2. **Sum the Volumes**: Add together the volumes of the valid titrations.<br />3. **Count the Valid Titrations**: Determine the number of valid titration measurements.<br />4. **Calculate the Average**: Divide the total volume by the number of valid titrations.<br />5. **Round the Result**: Round the average volume to two decimal places.<br /><br />Let's assume the following volumes were recorded in a series of titration experiments (excluding the trial titration result):<br /><br />- Titration 1: 24.50 mL<br />- Titration 2: 24.70 mL<br />- Titration 3: 24.60 mL<br /><br />### Step-by-Step Calculation:<br /><br />1. **Sum the Volumes**:<br /> \[\text{Total Volume} = 24.50 + 24.70 + 24.60 = 73.80 \text{ mL}\]<br /><br />2. **Count the Valid Titrations**:<br /> \[\text{Number of Valid Titrations} = 3\]<br /><br />3. **Calculate the Average**:<br /> \[\text{Average Volume} = \frac{\text{Total Volume}}{\text{Number of Valid Titrations}} = \frac{73.80}{3} = 24.60 \text{ mL}\]<br /><br />4. **Round the Result**:<br /> The average volume is already at two decimal places.
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