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x & f(x) 0 & 100 1 & 120 2 & 144 3 & 172.8

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x & f(x) 
 0 & 100 
1 & 120 
2 & 144 
3 & 172.8

x & f(x) 0 & 100 1 & 120 2 & 144 3 & 172.8

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VanceElite · Tutor for 8 years

Answer

The function is \(f(x) = 100 \times 1.2^x\).

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## Step 1: Observing the given values<br />We are given a table with two columns, where the left column represents values of \(x\) and the right column represents corresponding values of a function \(f(x)\).<br /><br />- When \(x = 0\), \(f(x) = 100\).<br />- When \(x = 1\), \(f(x) = 120\).<br />- When \(x = 2\), \(f(x) = 144\).<br />- When \(x = 3\), \(f(x) = 172.8\).<br /><br />## Step 2: Identifying the pattern<br />- The value of \(f(x)\) increases as \(x\) increases.<br />- The ratio of consecutive \(f(x)\) values seems consistent. To confirm this, we calculate the ratio of each pair of consecutive values:<br />- \(\frac{120}{100} = 1.2\)<br />- \(\frac{144}{120} = 1.2\)<br />- \(\frac{172.8}{144} = 1.2\)<br />- This consistent ratio suggests that the function \(f(x)\) could be an exponential function where each step involves multiplying by a constant factor, in this case, 1.2.<br /><br />## Step 3: Formulating the function<br />- Given the pattern, the function can be expressed as \(f(x) = 100 \times 1.2^x\). This formula fits all the given data points.<br /><br />## Step 4: Verifying the function<br />- For \(x = 0\), \(f(0) = 100 \times 1.2^0 = 100\).<br />- For \(x = 1\), \(f(1) = 100 \times 1.2^1 = 120\).<br />- For \(x = 2\), \(f(2) = 100 \times 1.2^2 = 144\).<br />- For \(x = 3\), \(f(3) = 100 \times 1.2^3 = 172.8\).<br />- The function \(f(x) = 100 \times 1.2^x\) correctly produces all the values in the table.<br /><br />## Step 5: Conclusion<br />- The function \(f(x)\) is an exponential function where the base value is 100, and it is multiplied by 1.2 for each increase in \(x\) by 1.
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