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19240 people work at a factory. Of these people 150 have a car 110 have a bicycle 65 of the people who have a bicycle do not have a car. (a) Use this information to complete the frequency tree. have a bicycle square have a car do not have a bicycle square 240 have a bicycle x do not have a car square do not have a bicycle square

Question

19240 people work at a factory.
Of these people
150 have a car
110 have a bicycle
65 of the people who have a bicycle do not have a car.
(a) Use this information to complete the frequency tree.
have a bicycle
square 
have a car
do not
have a bicycle
square 
240
have a bicycle x
do not
have a car
square 
do not
have a bicycle
square

19240 people work at a factory. Of these people 150 have a car 110 have a bicycle 65 of the people who have a bicycle do not have a car. (a) Use this information to complete the frequency tree. have a bicycle square have a car do not have a bicycle square 240 have a bicycle x do not have a car square do not have a bicycle square

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YvetteElite · Tutor for 8 years

Answer

lright, before starting to solve this problem, let's clearly outline what the question is asking. This factory has a total of 19240 workers. We know that 150 workers have a car, 110 workers have a bicycle, and specifically, 65 employees, who own a bicycle do not own any cars. We are aimed to generate the frequency tree based on these statistics.<br /><br />Step 1: We start by mapping out the tree with the given information.<br /><br /> Everyone (N = 19240)<br /><br /> / \<br /><br /> Has Bike() Does not has bike ()<br /><br /> / \ / \<br /><br /> Has Car () No Car() Has Car() No car()<br /><br />At this stage, we need to fill the side branch first. Let's do the side with the bike since that's where we have more information.<br /><br />Step 2: Out of 110 bicycle holder, 65 do not possess a car. Thus, subtracting these 65 from the total of 110, we now clear that 45 bicycle holders do have car.<br /><br />So our tree now looks like this:<br /> <br /> Everyone (N = 19240)<br /><br /> / \<br /><br /> Has Bike(110) Does not has bike ()<br /><br /> / \ / \<br /><br /> Has Car (45) No Car(65) Has Car() No car()<br /><br />Step 3: It is specified that a total of 150 workers own a car, so if already 45 of the car owners also have a bike, then 105 car owners do not have bike.<br /><br />Now we update our tree with this information :<br /><br /> Everyone (N = 19240)<br /><br /> / \<br /><br />ior<br /><br /> Has Bike(110) ужеSmoothens ./djt<br /><br /> / \ ipvSpy \<br />tdDCtranscopiesData.data.e silentDPrem<br /><br />Has Car (45) No Car(65) Has oak.ream dane.masxCachePathtese prior ( w i drincar(105) no c<br /><br /> |wwa-Param.-menis.uor strrbc.). has meons"<br /><br /> <br />With the quantities placed in the car and bike sections, we are missing only the portion that reports for the total workers who perform with neither a car nor a cycles.<br /><br />Showrite fin p ethpor Last constitution, auts the forms canontains attributed from disk consists across four, forks are sourced rom diskctabl babry Etilap snpaStalwtrello tn_bg and hpForHe old use<br /><br />Step 4: Subtracting from the total amount (19240) the 150 who own car, and the 65 who only have bikes, we clear that out that 19025 workers do not have either a car or bike.<br /> <br /><br />That being said, the final frequency tree will look like:<br /><br /> Everyone (N = 19240)<br /><br /> / \<br /><br /> Has Bike(110) Does not has bike (19130)<br /><br /> / \ / \<br /><br /> Has Car (45) No Car(65) Has Car(105) No Car(19025)<br /><br />Hence, careful tracking and subtraction have given us wrap up this frequency distribution tree **correctly**. <br />Note to assign the found numeral and fetch next calculations going through respective steps. This will not only discern reliable tracking of your numbers and deduction, but it will also add cleaning within information depicted.
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