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Which is the formula mass of (NH_(4))_(2)SO_(4) 96.07 amu 114.12 amu 116.17 amu 132.17 amu

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Which is the formula mass of (NH_(4))_(2)SO_(4)
96.07 amu
114.12 amu
116.17 amu
132.17 amu

Which is the formula mass of (NH_(4))_(2)SO_(4) 96.07 amu 114.12 amu 116.17 amu 132.17 amu

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ZephyrMaster · Tutor for 5 years

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### \( 132.17 \) amu

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## Step1: Identify the atomic masses of each element<br />- Atomic masses:<br /> - N (Nitrogen) = 14.01 amu<br /> - H (Hydrogen) = 1.01 amu<br /> - S (Sulfur) = 32.06 amu<br /> - O (Oxygen) = 16.00 amu<br /><br />## Step2: Calculate the total atomic mass for $\left(\mathrm{NH}_{4}\right)_{2}$<br />### - Two nitrogen atoms: \(2 \times 14.01\) amu<br /> - Eight hydrogen atoms: \(8 \times 1.01\) amu<br /> - Individual sum: \(2 \times 14.01 + 8 \times 1.01 = 28.02 + 8.08 = 36.10\) amu<br /><br />## Step3: Calculate the total atomic mass for $\mathrm{SO}_{4}$<br />### - One sulfur atom: \(1 \times 32.06\) amu<br /> - Four oxygen atoms: \(4 \times 16.00\) amu<br /> - Individual sum: \(32.06 + 4 \times 16.00 = 32.06 + 64.00 = 96.06\) amu<br /><br />## Step4: Combine the calculated masses<br />### - Total mass: \(\left(\mathrm{NH}_{4}\right)_{2} + \mathrm{SO}_{4} \)<br /> - Overall sum: \(36.10 + 96.06 = 132.16\) amu<br /><br />#
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