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Find the volume of hydrogen gas that reacts with 160cm^3 of oxygen gas measured at the same temperature and pressure. 2H_(2)(g)+O_(2)(g)arrow 2H_(2)O(l) __ ".

Question

Find the volume of hydrogen gas that reacts with
160cm^3 of
oxygen gas measured at the same temperature and pressure.
2H_(2)(g)+O_(2)(g)arrow 2H_(2)O(l)
__
".

Find the volume of hydrogen gas that reacts with 160cm^3 of oxygen gas measured at the same temperature and pressure. 2H_(2)(g)+O_(2)(g)arrow 2H_(2)O(l) __ ".

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FelixVeteran · Tutor for 10 years

Answer

To react/emulsify 160 \( \mathrm{cm}^{3} \) of \( \mathrm{O}_{2} \) gas completely, we need twice of 160 i.e. \( 2 \times 160 = 320 \) \( \mathrm{cm}^{3} \) of \( \mathrm{H}_{2} \) gas.

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## Step 1: <br />Identify the stoichiometric ratio of \( \mathrm{H}_{2} \) molecules to \( \mathrm{O}_{2} \) molecules from the balanced chemical equation. Here, the ratio is 2:1<br /><br />## Step 2: <br />Apply this ratio to find the volume of \( \mathrm{H}_{2} \) gas required to completely react with given volume (160 \( \mathrm{cm}^{3} \)) of \( \mathrm{O}_{2} \) gas. So, double volume of \( \mathrm{H}_{2} \) is required for 1 volume of \( \mathrm{O}_{2} \) gas for complete reaction with no leftovers.
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