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Magnesium reacts with a certain element to form a compound with the general formula MgX. What would the most likely formula be for the compound formed between 10 assum and element X? K_(2)X KX_(2) K_(2)X_(3) K_(2)X_(2)

Question

Magnesium reacts with a certain element to form a compound with the general formula MgX. What would the most likely formula be for the compound formed between 10 assum
and element X?
K_(2)X
KX_(2)
K_(2)X_(3)
K_(2)X_(2)

Magnesium reacts with a certain element to form a compound with the general formula MgX. What would the most likely formula be for the compound formed between 10 assum and element X? K_(2)X KX_(2) K_(2)X_(3) K_(2)X_(2)

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IanMaster · Tutor for 5 years

Answer

The most likely formula for the compound formed between potassium (K) and element X, based on the charge balance principle, is \(k_{2} \mathrm{x}\).

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The chemical formula \(\mathrm{MgX}\) indicates that magnesium (Mg) is combining with element X in a 1:1 ratio. Since magnesium typically has a +2 charge (as it is in group 2 of the periodic table and loses two electrons to achieve a noble gas configuration), we can infer that element X must have a -2 charge to balance the charge of magnesium in the compound \(\mathrm{MgX}\).Now, considering the element potassium (K), which is in group 1 of the periodic table, it typically has a +1 charge because it loses one electron to achieve a noble gas configuration. To form a neutral compound with element X (which we have determined has a -2 charge), we would need two potassium ions to balance the -2 charge of a single X ion. This would result in a formula of \(\mathrm{K}_{2}X\), where the subscript 2 indicates that there are two potassium ions for every one ion of element X.Let's evaluate the given options:- \(k_{2} \mathrm{x}\): This formula shows two potassium ions for every one ion of element X, which is correct based on our charge balance reasoning.- \(\mathrm{KX}_{2}\): This formula suggests one potassium ion for every two ions of element X, which would not be charge balanced since potassium has a +1 charge and X has a -2 charge.- \(\mathrm{K}_{2} \mathrm{X}_{3}\): This formula suggests two potassium ions for every three ions of element X, which would also not be charge balanced.- \(K_{2} X_{2}\): This formula suggests two potassium ions for every two ions of element X, which would not be charge balanced either.
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