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Last Answered 9/6/24 Complete the following equation for the IONISATION of sodium hydroxide in water.[Pay attention to both the STATE 5YMBOLS and the CHARGES in 5UPERSCRIPT] NaOH(s)arrow Na^+(aq)+OH^-(aq) NaOH(s)arrow Na^-(aq)+OH^+(aq) NaOH(s)arrow Na^+(s)+OH^-(s) NaOH(s)arrow Na^-(s)+OH^+(s)

Question

Last Answered 9/6/24
Complete the following equation for the IONISATION of
sodium hydroxide in water.[Pay attention to both the STATE
5YMBOLS and the CHARGES in 5UPERSCRIPT]
NaOH(s)arrow Na^+(aq)+OH^-(aq)
NaOH(s)arrow Na^-(aq)+OH^+(aq)
NaOH(s)arrow Na^+(s)+OH^-(s)
NaOH(s)arrow Na^-(s)+OH^+(s)

Last Answered 9/6/24 Complete the following equation for the IONISATION of sodium hydroxide in water.[Pay attention to both the STATE 5YMBOLS and the CHARGES in 5UPERSCRIPT] NaOH(s)arrow Na^+(aq)+OH^-(aq) NaOH(s)arrow Na^-(aq)+OH^+(aq) NaOH(s)arrow Na^+(s)+OH^-(s) NaOH(s)arrow Na^-(s)+OH^+(s)

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QuentinProfessional · Tutor for 6 years

Answer

\[\boxed{\mathrm{NaOH}(\mathrm{s}) \longrightarrow \mathrm{Na}^{+}(\mathrm{aq}) + \mathrm{OH}^{-}(\mathrm{aq})}\]

Explain

## Step 1:<br />Sodium hydroxide (NaOH) is a strong base, which means it dissociates completely in water. In this process, sodium hydroxide splits into sodium ions (Na^+) and hydroxide ions (OH^-).<br /><br />## Step 2:<br />We need to pay attention to both the state symbols and the charges in superscript. When NaOH dissociates in water, the sodium ion (Na^+) and hydroxide ion (OH^-) are both in aqueous form (aq).<br /><br />## Step 3:<br />We can represent this dissociation with the balanced chemical equation:<br />\[\mathrm{NaOH}(\mathrm{s}) \longrightarrow \mathrm{Na}^{+}(\mathrm{aq}) + \mathrm{OH}^{-}(\mathrm{aq})\]<br /><br />## Step 4:<br />Looking at the given options, we see that the correct representation of this dissociation is:<br />\[\mathrm{NaOH}(\mathrm{s}) \longrightarrow \mathrm{Na}^{+}(\mathrm{aq}) + \mathrm{OH}^{-}(\mathrm{aq})\]
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