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The relative formula mass of the co mpounc CO_(x) is 44. Find x. A_(r) of Carbon (C)=12 A_(r) of Oxygen(O)=16 A_(r) of Hydrogen (H)=1

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The relative formula mass of the co mpounc
CO_(x) is 44. Find x.
A_(r) of Carbon (C)=12
A_(r) of Oxygen(O)=16
A_(r) of Hydrogen (H)=1

The relative formula mass of the co mpounc CO_(x) is 44. Find x. A_(r) of Carbon (C)=12 A_(r) of Oxygen(O)=16 A_(r) of Hydrogen (H)=1

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AneiraExpert · Tutor for 3 years

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After performing the calculation, we find that \( x = 2 \). Therefore, the compound \( \mathrm{CO}_{\mathrm{x}} \) is actually \( \mathrm{CO}_{2} \), which is carbon dioxide.

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## Step 1: Understand the problem<br />The problem is asking us to find the number of oxygen atoms in the compound \( \mathrm{CO}_{\mathrm{x}} \) given that the relative formula mass of the compound is 44. The atomic masses of carbon (C), oxygen (O), and hydrogen (H) are given as 12, 16, and 1 respectively.<br /><br />## Step 2: Formulate the equation<br />The relative formula mass of a compound is the sum of the atomic masses of all the atoms in the compound. In this case, the relative formula mass of \( \mathrm{CO}_{\mathrm{x}} \) is the sum of the atomic mass of carbon and the atomic mass of oxygen multiplied by \( \mathrm{x} \). <br /><br />### \( 12 + 16x = 44 \)<br /><br />## Step 3: Solve the equation<br />We can solve the equation for \( \mathrm{x} \) by subtracting 12 from both sides and then dividing by 16.<br /><br />### \( x = \frac{44 - 12}{16} \)
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