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5. Calculate the atomic mass of Iron just like you did for M8Mium. The following are the known isotopes for iron: (show all work) Fe-54-5.945% Fe-56-91.85% Fe-57-2.03% Fe-58-0.282%

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5. Calculate the atomic mass of Iron just like you did for M8Mium. The following are the known
isotopes for iron: (show all work)
Fe-54-5.945% 
Fe-56-91.85% 
Fe-57-2.03% 
Fe-58-0.282%

5. Calculate the atomic mass of Iron just like you did for M8Mium. The following are the known isotopes for iron: (show all work) Fe-54-5.945% Fe-56-91.85% Fe-57-2.03% Fe-58-0.282%

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TerrenceElite · Tutor for 8 years

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# Explanation:<br />## Step1: Identify Isotopes and Their Abundances<br />### List the isotopes of iron and their respective natural abundances: $Fe-54$ (5.945%), $Fe-56$ (91.85%), $Fe-57$ (2.03%), and $Fe-58$ (0.282%).<br />## Step2: Convert Percentages to Decimal Form<br />### Convert the given percentages to decimal form by dividing each by 100:<br />\[\text{Abundance of } Fe-54 = \frac{5.945}{100} = 0.05945\]<br />\[\text{Abundance of } Fe-56 = \frac{91.85}{100} = 0.9185\]<br />\[\text{Abundance of } Fe-57 = \frac{2.03}{100} = 0.0203\]<br />\[\text{Abundance of } Fe-58 = \frac{0.282}{100} = 0.00282\]<br />## Step3: Multiply Each Isotope's Mass by Its Abundance<br />### Calculate the contribution of each isotope to the atomic mass by multiplying the mass number by the decimal abundance:<br />\[\text{Contribution of } Fe-54 = 54 \times 0.05945 = 3.2093\]<br />\[\text{Contribution of } Fe-56 = 56 \times 0.9185 = 51.436\]<br />\[\text{Contribution of } Fe-57 = 57 \times 0.0203 = 1.1571\]<br />\[\text{Contribution of } Fe-58 = 58 \times 0.00282 = 0.16356\]<br />## Step4: Sum the Contributions<br />### Add the contributions of each isotope to find the total atomic mass:<br />\[\text{Atomic Mass of Iron} = 3.2093 + 51.436 + 1.1571 + 0.16356 = 55.966\]<br /><br /># Answer: <br />### The atomic mass of Iron is approximately 55.966 amu.
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