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What is the factored form of the expression over the complex numbers? 4x^2+25y^2 (2x+5iy)(2x+5iy) (2x-5iy)(2x-5iy) (2x-5y)(2x+5y) (2x+5iy)(2x-5iy)

Question

What is the factored form of the expression over the complex numbers?
4x^2+25y^2
(2x+5iy)(2x+5iy)
(2x-5iy)(2x-5iy)
(2x-5y)(2x+5y)
(2x+5iy)(2x-5iy)

What is the factored form of the expression over the complex numbers? 4x^2+25y^2 (2x+5iy)(2x+5iy) (2x-5iy)(2x-5iy) (2x-5y)(2x+5y) (2x+5iy)(2x-5iy)

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MennaMaster · Tutor for 5 years

Answer

The factored form of the expression \(4 x^{2}+25 y^{2}\) over the complex numbers is \((2x + 5yi)(2x - 5yi)\).

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## Step 1<br />The given expression is \(4 x^{2}+25 y^{2}\). We need to factorize this expression over the complex numbers.<br /><br />## Step 2<br />The formula for the difference of squares is \(a^2 - b^2 = (a + b)(a - b)\). However, the given expression is a sum of squares, not a difference.<br /><br />## Step 3<br />We can use the identity \(a^2 + b^2 = (a + bi)(a - bi)\) to factorize a sum of squares. Here, \(i\) is the imaginary unit, and \(i^2 = -1\).<br /><br />## Step 4<br />Substitute \(a = 2x\) and \(b = 5y\) into the identity. We get:<br /><br />### \((2x)^2 + (5y)^2 = (2x + 5yi)(2x - 5yi)\)
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