The diagram shows a prism placed on a horizontal floor. The prism has height 5m The volume of the prism is 30m^(3) The pressure on the floor due to the prism is 55 newtons //m^(2) Work out the force exerted by the prism on the floor.

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The diagram shows a prism placed on a horizontal floor. The prism has height 5m The volume of the prism is 30m^(3) The pressure on the floor due to the prism is 55 newtons //m^(2) Work out the force exerted by the prism on the floor.

Answer 1

The force exerted by the prism on the floor is 3300 Newtons.

Answer 2

1. To find the force exerted by the prism on the floor, we can use the formula for pressure, which is defined as pressure \(P = \frac{Force}{Area}\). 2. In this case, we are given the pressure exerted by the prism on the floor (\(P = 55 \, \text{N/m}^2\)) and the volume of the prism (\(V = 30 \, \text{m}^3\)). The height of the prism is also provided (\(h = 5 \, \text{m}\)). 3. To find the force exerted, we first need to determine the area of the base of the prism. We can calculate the area of the base (\(A\)) using the volume formula for a prism, which is \(V = A \times h\). Rearranging this formula to find the area gives us \(A = \frac{V}{h}\). 4. Substituting the given values for volume and height into this formula, we get: \[A = \frac{30 \, \text{m}^3}{5 \, \text{m}} = 6 \, \text{m}^2\] 5. Now, using the pressure formula and solving for the force (\(F\)), we have \(F = P \times A\). Substituting the given pressure and the calculated area into this formula, we get: \[F = 55 \, \text{N/m}^2 \times 6 \, \text{m}^2 = 330 \, \text{N}\] 6. Therefore, the force exerted by the prism on the floor is 3300 Newtons.

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The diagram shows a prism placed on a horizontal floor. The prism has height 5m The volume of the prism is 30m^(3) The pressure on the floor due to the prism is 55 newtons //m^(2) Work out the force exerted by the prism on the floor.

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