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A chemistry teacher provides students with the amount of potassium hydroxide they need in solution form. The teacher makes the solution by dissolving 42.1 grams of mathrm(KOH) into 3.0 mathrm(~L) of solution. What is the molarity of this solution? A 1.3 mathrm(M) B 0.44 mathrm(M) C 0.25 mathrm(M)

Question

A chemistry teacher provides students with the amount of potassium hydroxide they need in solution form. The teacher makes the solution by dissolving 42.1 grams of mathrm(KOH) into 3.0 mathrm(~L) of solution.
What is the molarity of this solution?
A 1.3 mathrm(M) 
B 0.44 mathrm(M) 
C 0.25 mathrm(M)

A chemistry teacher provides students with the amount of potassium hydroxide they need in solution form. The teacher makes the solution by dissolving 42.1 grams of mathrm(KOH) into 3.0 mathrm(~L) of solution. What is the molarity of this solution? A 1.3 mathrm(M) B 0.44 mathrm(M) C 0.25 mathrm(M)

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MillieMaster · Tutor for 5 years

Answer

The molarity of the solution is C) 0.25M.

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## Step 1<br />Molarity (M) is defined as the number of moles of a substance per liter of solution. It can be calculated using the formula:<br /><br />### **M = \frac{mol}{L}**<br /><br />## Step 2<br />To find the molarity of the KOH solution, we first need to find the number of moles of KOH. The molar mass of KOH (where K=39.1, O=16, H=1) is approximately 56.1 g/mol.<br /><br />## Step 3<br />The number of moles is calculated by dividing the mass of the substance by its molar mass.<br /><br />### **Number of mol = \frac{mass(g)}{molar mass(g/mol)} = \frac{42.1g}{56.1g/mol} = 0.75 mol**<br /><br />## Step 4<br />Since the solution is prepared to a total volume of 3.0 L, we can now calculate the molarity.<br /><br />### **M = \frac{mol}{L} = \frac{0.75 mol}{3 L} = 0.25 mol/L**<br /><br />Therefore, the correct answer is C) 0.25M.
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