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Acid rain can be destructive to both the natural environment and human-made structures. The equation below shows a reaction that occurs that may lead to the formation of acid rain. 3NO_(2)+H_(2)Oarrow 2HNO_(3)+NO How many moles (precise to the nearest 0.01 mol) of nitric acid are produced from 300:00 mol of nitrogen dioxide? 200.00 mol 200.09 mol 450.00 mol 450.02 mol

Question

Acid rain can be destructive to both the natural environment and human-made structures. The equation below shows a
reaction that occurs that may lead to the formation of acid rain.
3NO_(2)+H_(2)Oarrow 2HNO_(3)+NO
How many moles (precise to the nearest 0.01 mol) of nitric acid are produced from 300:00 mol of nitrogen dioxide?
200.00 mol
200.09 mol
450.00 mol
450.02 mol

Acid rain can be destructive to both the natural environment and human-made structures. The equation below shows a reaction that occurs that may lead to the formation of acid rain. 3NO_(2)+H_(2)Oarrow 2HNO_(3)+NO How many moles (precise to the nearest 0.01 mol) of nitric acid are produced from 300:00 mol of nitrogen dioxide? 200.00 mol 200.09 mol 450.00 mol 450.02 mol

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JenaProfessional · Tutor for 6 years

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A

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1. The balanced chemical equation given is \(3 \mathrm{NO}_{2} + \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{HNO}_{3} + \mathrm{NO}\). This equation tells us that 3 moles of nitrogen dioxide (\(\mathrm{NO}_{2}\)) react with water (\(\mathrm{H}_{2} \mathrm{O}\)) to produce 2 moles of nitric acid (\(\mathrm{HNO}_{3}\)) and 1 mole of nitric oxide (\(\mathrm{NO}\)).2. From the equation, we can set up a ratio to determine the amount of nitric acid produced from a given amount of nitrogen dioxide. The ratio is \(3 \mathrm{NO}_{2} : 2 \mathrm{HNO}_{3}\), or \(3/2\).3. Given that 300.00 moles of nitrogen dioxide are reacting, we can use the ratio to find the amount of nitric acid produced: \(\frac{2 \mathrm{HNO}_{3}}{3 \mathrm{NO}_{2}} \times 300.00 \mathrm{mol \, NO}_{2} = 200.00 \mathrm{mol \, HNO}_{3}\).4. Thus, 200.00 moles of nitric acid are produced from 300.00 moles of nitrogen dioxide.5. Among the given options, 200.00 mol (Option A) is the correct answer.
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