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(f) Si_(2)H_(6) reacts with oxygen. The equation for the reaction is: 2Si_(2)H_(6)(g)+7O_(2)(g)arrow 4SiO_(2)(s)+6H_(2)O(g) 30cm^3 of Si_(2)H_(6) is reacted with 150cm^3 (an excess) of oxygen. Calculate the total volume of gases present after the reaction. All volumes of gases are measured at the same temperature and pressure. __

Question

(f) Si_(2)H_(6) reacts with oxygen.
The equation for the reaction is:
2Si_(2)H_(6)(g)+7O_(2)(g)arrow 4SiO_(2)(s)+6H_(2)O(g)
30cm^3 of Si_(2)H_(6) is reacted with 150cm^3 (an excess) of oxygen.
Calculate the total volume of gases present after the reaction.
All volumes of gases are measured at the same temperature and pressure.
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(f) Si_(2)H_(6) reacts with oxygen. The equation for the reaction is: 2Si_(2)H_(6)(g)+7O_(2)(g)arrow 4SiO_(2)(s)+6H_(2)O(g) 30cm^3 of Si_(2)H_(6) is reacted with 150cm^3 (an excess) of oxygen. Calculate the total volume of gases present after the reaction. All volumes of gases are measured at the same temperature and pressure. __

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JustinExpert · Tutor for 3 years

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The total volume of gases present after the reaction is \( 240 \mathrm{~cm}^{3} \).

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## Step 1: <br />Firstly, we need to understand the stoichiometry of the given balanced chemical equation. It states that for every 2 moles of silane (\( \mathrm{Si}_{2} \mathrm{H}_{6} \)), 6 moles of water (\( \mathrm{H}_{2} \mathrm{O} \)) and 4 moles of silicon dioxide (\( \mathrm{SiO}_{2} \)) are produced. <br /><br />## Step 2: <br />Since the volume of gases is proportional to the number of moles at the same temperature and pressure (according to Avogadro's law), we can say that for every 2 volumes of silane, 6 volumes of water vapor are produced. <br /><br />## Step 3: <br />Given that we are reacting \( 30 \mathrm{~cm}^{3} \) of silane, we can calculate the volume of water vapor produced by using the ratio derived from the balanced equation. <br /><br />### \( \text{Volume of } \mathrm{H}_{2} \mathrm{O} = \frac{30 \mathrm{~cm}^{3} \text{ of silane} \times 6 \text{ volumes of water}}{2 \text{ volumes of silane}} = 90 \mathrm{~cm}^{3} \)<br /><br />## Step 4: <br />The total volume of gases after the reaction is the sum of the volume of the water vapor and the unreacted oxygen. <br /><br />### \( \text{Total volume of gases} = \text{Volume of } \mathrm{H}_{2} \mathrm{O} + \text{Volume of unreacted } \mathrm{O}_{2} = 90 \mathrm{~cm}^{3} + 150 \mathrm{~cm}^{3} = 240 \mathrm{~cm}^{3} \)
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