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6 Use the periodic table to work out which of these compounds has a relative formula mass of 100. CaCl_(2) H_(2)SO_(4) MgCO_(3) CaCO_(3)

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6 Use the periodic table to work out which of these compounds has a
relative formula mass of 100.
CaCl_(2)
H_(2)SO_(4)
MgCO_(3)
CaCO_(3)

6 Use the periodic table to work out which of these compounds has a relative formula mass of 100. CaCl_(2) H_(2)SO_(4) MgCO_(3) CaCO_(3)

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KieranElite · Tutor for 8 years

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<p> D</p>

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<p> First step to solve this problem requires knowledge of atomic masses of the elements which belong to respective compounds. The atomic mass usually, can be discovered using a periodic table. The relative formula mass (M_r) of a compound is the sum total of the atomic masses of each atom in its formula. Therefore, we need to calculate the formula mass of all four compounds (✓Chloroform - Plastic white (CaCl2), Sulfuric acid (H2SO4), Magnesium carbonate (MgCO3), and Calcium carbonate (CaCO3)) and to check which one has formula mass equal to 100. <br /><br />Atomic masses approximated to nearest whole number:<br />Calcium (Ca): 40<br />Chlorine (Cl): 35.5 <br />Hydrogen (H):1<br />Sulphur(S) - 32<br />Oxygen (O) - 16<br />Magnesium (Mg) - 24 and<br />Carbon (C) - 12<br /><br />Let's calculate the molecular masses of each of them. <br /><br />The mass of 𝐶𝑎𝐶𝑙2 = (1 x Mass of Ca) + (2 x Mass of Cl) = 40 + 2(35.5) =111 <br />The mass of H2SO4 = (2 x mass of \(H\)) + (1 x mass of \(S\)) + (4 x mass of \(O\)) =2+(1x32)+4(16)=98 <br /><br />The total mass of MgCO3 =(1 x mass of \(Mg\)) + (1 x mass of \(C\)) + (3 x mass of \(O\)) = 24+12+3*(16)=84 (Not '100')<br /><br />𝐶𝑎CO3's total mass = (1 x mass of Ca )+(1x This mass of \(C\)) + This mass of 3x\(O) about nutrition<br /> = 40+12+3*(16)=100 which is what we have been looking for.<br /><br /></p>
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